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如何在数组中获取json子代的值
EN

Stack Overflow用户
提问于 2020-01-20 12:03:07
回答 5查看 377关注 0票数 0

如何将此JSON文件中的bio和value链接到我正在使用android studio的字符串

代码语言:javascript
复制
{
  "Amber": [
    {
      "Info": {
        "name": "Amber",
        "bio": "Turkish-Cypriot",
        "image": "null"
      },
      "Class": {
        "Adorable": {
          "name": "",
          "link": ""
        },
        "IronAge": {
          "name": "",
          "link": ""
        }
      }
    }
  ]
}

我的java代码

代码语言:javascript
复制
    private void parseResult_GetWebData(String result) {
        try {
            JSONObject response = new JSONObject(result);
            JSONArray jsonArray = response.getJSONArray("Amber");

            for (int i = 0; i < jsonArray.length(); i++) {
                JSONObject jsonObject = jsonArray.optJSONObject(i);
                JSONObject jsonArray1 = jsonObject.getJSONObject("Info");
                JSONObject jsonArray2 = jsonObject.getJSONObject("Class");

                    String bio = jsonArray1.optString("bio");
                    String link = jsonArray2.optString("link");



            }

        } catch (JSONException e) {
            e.printStackTrace();
        }
    }

由于我的代码没有得到任何结果,我不知道到底在做什么工作。

EN

回答 5

Stack Overflow用户

发布于 2020-01-20 13:36:58

你应该使用数据模型,即标准的方式。

主POJO类

代码语言:javascript
复制
public class MyModel
{
    private Amber[] Amber;

    public Amber[] getAmber ()
    {
        return Amber;
    }

    public void setAmber (Amber[] Amber)
    {
        this.Amber = Amber;
    }

    @Override
    public String toString()
    {
        return "[Amber = "+Amber+"]";
    }
}

Amber.java

代码语言:javascript
复制
public class Amber
{
    private Class Class;

    private Info Info;

    //Can not getClass name of this method becuase getClass method is define in Object class so make it just getClassi or anything else.
    public Class getClassi ()
    {
        return Class;
    }

    public void setClass (Class Class)
    {
        this.Class = Class;
    }

    public Info getInfo ()
    {
        return Info;
    }

    public void setInfo (Info Info)
    {
        this.Info = Info;
    }

    @Override
    public String toString()
    {
        return "Amber [Class = "+Class+", Info = "+Info+"]";
    }
}

Class.java

代码语言:javascript
复制
public class Class
{
    private Adorable Adorable;

    private IronAge IronAge;

    public Adorable getAdorable ()
    {
        return Adorable;
    }

    public void setAdorable (Adorable Adorable)
    {
        this.Adorable = Adorable;
    }

    public IronAge getIronAge ()
    {
        return IronAge;
    }

    public void setIronAge (IronAge IronAge)
    {
        this.IronAge = IronAge;
    }

    @Override
    public String toString()
    {
        return "Info [Adorable = "+Adorable+", IronAge = "+IronAge+"]";
    }
}

IronAge.java

代码语言:javascript
复制
public class IronAge
{
    private String name;

    private String link;

    public String getName ()
    {
        return name;
    }

    public void setName (String name)
    {
        this.name = name;
    }

    public String getLink ()
    {
        return link;
    }

    public void setLink (String link)
    {
        this.link = link;
    }

    @Override
    public String toString()
    {
        return "IronAge [name = "+name+", link = "+link+"]";
    }
}

Adorable.java

代码语言:javascript
复制
public class Adorable
{
    private String name;

    private String link;

    public String getName ()
    {
        return name;
    }

    public void setName (String name)
    {
        this.name = name;
    }

    public String getLink ()
    {
        return link;
    }

    public void setLink (String link)
    {
        this.link = link;
    }

    @Override
    public String toString()
    {
        return "Adorable [name = "+name+", link = "+link+"]";
    }
}

Info.java

代码语言:javascript
复制
public class Info
{
    private String image;

    private String name;

    private String bio;

    public String getImage ()
    {
        return image;
    }

    public void setImage (String image)
    {
        this.image = image;
    }

    public String getName ()
    {
        return name;
    }

    public void setName (String name)
    {
        this.name = name;
    }

    public String getBio ()
    {
        return bio;
    }

    public void setBio (String bio)
    {
        this.bio = bio;
    }

    @Override
    public String toString()
    {
        return " class [image = "+image+", name = "+name+", bio = "+bio+"]";
    }
}

现在使用GSON将JSON数据解析为模型类。

这是GSON的Gradle依赖项

代码语言:javascript
复制
dependencies {
  implementation 'com.google.code.gson:gson:2.8.6'
}
代码语言:javascript
复制
public void parse(String jsonString){
        Gson gson = new Gson();
        MyModel model = gson.fromJson(jsonString, MyModel.class);
        for(Amber amber : model.getAmber()){
            //TO GET Links
            String link1 = amber.getClassi().getAdorable().getLink();
            String link2 = amber.getClassi().getIronAge().getLink(); 
        }
    }

您可以使用this将JSON转换为pojo模型类。

票数 4
EN

Stack Overflow用户

发布于 2020-01-20 12:13:42

Class是包含多个JSONObject'sJSOnObject,因此在获得Class之后,您需要遍历每个JSONObject以获得link

代码语言:javascript
复制
JSONObject jsonObject2 = jsonObject.getJSONObject("Class");
Iterator<String> itr = jsonObject2.keys();

while(itr.hasNext())  {

     JSONObject innerObj = jsonObject2.getJSONObject(itr.next());
     String link = innerObj.optString("link");
   }
票数 0
EN

Stack Overflow用户

发布于 2020-01-20 12:19:37

请检查以上代码的更新响应。在我的系统中,我成功地执行了代码,没有崩溃和值输出。

代码语言:javascript
复制
        try {
            String json= "{\n" +
                    "  \"Amber\": [\n" +
                    "    {\n" +
                    "      \"Info\": {\n" +
                    "        \"name\": \"Amber\",\n" +
                    "        \"bio\": \"Turkish-Cypriot\",\n" +
                    "        \"image\": \"null\"\n" +
                    "      },\n" +
                    "      \"Class\": {\n" +
                    "        \"Adorable\": {\n" +
                    "          \"name\": \"\",\n" +
                    "          \"link\": \"\"\n" +
                    "        },\n" +
                    "        \"IronAge\": {\n" +
                    "          \"name\": \"\",\n" +
                    "          \"link\": \"\"\n" +
                    "        }\n" +
                    "      }\n" +
                    "    }\n" +
                    "  ]\n" +
                    "}";
            JSONObject jsonObject = new JSONObject(json);
            JSONArray jsonArrayAmber= jsonObject.getJSONArray("Amber");
            for(int i=0; i<jsonArrayAmber.length(); i++) {
                JSONObject jsonObject1= jsonArrayAmber.getJSONObject(i).getJSONObject("Info");
                if(jsonObject1!=null) {
                    String bioValue= jsonObject1.getString("bio");
                    System.out.println("jsonTest "+bioValue);
                }
                JSONObject jsonObject2= jsonArrayAmber.getJSONObject(i).getJSONObject("Class");
                if(jsonObject2!=null) {
                    JSONObject jsonObjectAdorable = jsonObject2.getJSONObject("Adorable");
                    if(jsonObjectAdorable!=null) {
                        String linkAdorable = jsonObjectAdorable.getString("link");
                        System.out.println("jsonTest "+linkAdorable);
                    }
                    JSONObject jsonObjectIronAge = jsonObject2.getJSONObject("IronAge");
                    if(jsonObjectIronAge!=null) {
                        String IronAgeLink = jsonObjectIronAge.getString("link");
                        System.out.println("jsonTest "+ IronAgeLink);
                    }
                }
            }
    } catch (Exception e){
        e.printStackTrace();
    }
票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/59816857

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