我正在尝试关闭所有打开的订单,它们都是MarketOrders而不是PendingOrders,并且SL和TP设置为0,所以它们不应该关闭自己(它们仍然在终端中打开)。我将票证存储在数组中,因此我的循环如下所示:
for(int i = 0; i < trades.size(); ++i) OrderClose(tickets[i], lots[i], Bid, Slippage);但是我仍然收到“无效票证”的错误,你能告诉我为什么吗?这种情况并不总是发生,比如一些订单被关闭,一些订单被抛出无效的罚单。我没有注意到只有一个顺序的行为,所以我假设只有当有更多的顺序时才会发生。
代码:
template < typename T >
struct vector {
vector() {}
vector(int arraySize) {
if (arraySize < 0) { arraySize *= -1; }
ArrayResize(m_data, arraySize);
}
vector(vector & rhs) {
if (size() < rhs.size()) { ArrayResize(m_data, rhs.size()); }
for(uint i = 0; i < size(); ++i) { m_data[i] = rhs.m_data[i]; }
}
vector operator=(vector & rhs) {
if (size() < rhs.size()) { ArrayResize(m_data, rhs.size()); }
for(uint i = 0; i < size(); ++i) { m_data[i] = rhs.m_data[i]; }
return this;
}
T operator[](uint index) { return m_data[index]; }
void push_back( T value ) {
ArrayResize(m_data, ArraySize(m_data) + 1);
m_data[ ArraySize(m_data) - 1 ] = value;
}
uint size() { return ArraySize(m_data); }
void resize(uint newSize) { ArrayResize(m_data, newSize); }
void erase() {
ZeroMemory(m_data);
ArrayResize(m_data, 0);
}
void assign(uint index, T value) {
m_data[index] = value;
}
private:
T m_data[];
};
string Buy(double lots) {
string alertString = "";
int __ticket;
if ( (__ticket = OrderSend (Symbol(), OP_BUY, lots, Ask, Slippage, 0, 0, NULL, m_magic)) != -1 )
{
m_buyTicket.push_back( __ticket );
m_buyLots.push_back( lots );
m_buyPrice.push_back( Ask );
m_buyAccel.push_back( lots / Lots );
m_buyPos.push_back( 0 );
alertString = "Buy function call." +
"\nAsk\t= " + (string)Round(Ask) +
"\nBid\t= " + (string)Round(Bid) +
"\nLots\t= " + (string)Round(lots) +
"\nSpread\t= " + (string)m_spread +
"\nID\t= " + (string)CountAll();
}
else {
int _error = GetLastError();
alertString = "Error " + (string)_error + "\n" + TranslateError( _error );
}
return alertString;
}
string CloseAll() {
string alertString = "CloseAll function call.";
// Buy closing
for (uint i = 0; i < m_buyPrice.size(); ++i)
{
if ( OrderClose ( m_buyTicket[i], m_buyLots[i], Bid, Slippage) )
{
alertString += "\nBuy " + (string)(i+1) + " closed with profit " +
(string)Shrink ( (Bid - m_buyPrice[i]) * m_buyAccel[i] );
}
else
{
int _error = GetLastError();
alertString += "\nError " + (string)_error + "\n" + TranslateError( _error ) +
"\n(while closing Buy " + (string)(i+1) + ")";
}
}
// Sell closing
for (uint i = 0; i < m_sellPrice.size(); ++i)
{
if ( OrderClose ( m_sellTicket[i], m_sellLots[i], Ask, Slippage) )
{
alertString += "\nSell " + (string)(i+1) + " closed with profit " +
(string)Shrink ( (m_sellPrice[i] - Ask) * m_sellAccel[i] );
}
else
{
int _error = GetLastError();
alertString += "\nError " + (string)_error + "\n" + TranslateError( _error ) +
"\n(while closing Sell " + (string)(i+1) + ")";
}
}
return alertString;
}发布于 2020-01-29 02:21:05
当您成功关闭某些票据时,您不会将其从列表trades中删除,对吗?看起来你应该这么做。如果order close成功,则使用结构清除元素。顺便说一句,可能不需要重新发明轮子,使用CArrayObj作为元素的容器,并在订单关闭后删除它们。
https://stackoverflow.com/questions/59948194
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