在训练数据集中,datetime列是一个对象。本栏第一行: 2009-06-15 17:26:21 UTC。我试着拆分数据
train['Date'] = train['pickup_datetime'].str.slice(0,11)
train['Time'] = test['pickup_datetime'].str.slice(11,19)这样我就可以将日期和时间拆分为两个变量,并将它们更改为datetime数据类型。尝试了很多方法,但都不能得到结果。
train['Date']=pd.to_datetime(train['Date'], format='%Y-%b-%d')我还尝试拆分日期、时间和UTC
train['DateTime'] = pd.to_datetime(train['DateTime'])请为此建议一个代码。我是个乞讨者。
提前感谢
发布于 2019-12-02 17:20:24
我会尝试以下几种方法
import pandas as pd
#create some random dates matching your formatting
df = pd.DataFrame({"date": ["2009-06-15 17:26:21 UTC", "2010-08-16 19:26:21 UTC"]})
#convert to datetime objects
df["date"] = pd.to_datetime(df["date"])
print(df["date"].dt.date) #returns the date part without tz information
print(df["date"].dt.time) #returns the time part 输出:
0 2009-06-15
1 2010-08-16
Name: date, dtype: object
0 17:26:21
1 19:26:21
Name: date, dtype: object欲了解更多信息,请随时查阅文档:dt.date dt.time
对于您的特定情况:
#convert to datetime object
df['pickup_datetime']= pd.to_datetime(df['pickup_datetime'])
# seperate date and time
df['Date'] = df['pickup_datetime'].dt.date
df['Time'] = df['pickup_datetime'].dt.timehttps://stackoverflow.com/questions/59135423
复制相似问题