字符串格式随机值加法结果错误

Question

我正在尝试编写一个脚本，该脚本接收许多所需的随机数作为输入，然后生成并打印它们。

但是，我的脚本将数字相加，而不是连接字符串。我想让字符串加入，这样它就会生成引脚，如下所示：

输入要生成的午餐馅饼数量: 10

26141
128111
937502
2436
56516
83623
246317

我的代码：

import random

PTG = int(input("Enter the amount of pins to generate: \n"))
PG = 0
PS = ""

while PTG > PG:
 RN1 = random.randint(0, 9)
 RN2 = random.randint(0, 9)
 RN3 = random.randint(0, 9)
 RN4 = random.randint(0, 9)
 RN5 = random.randint(0, 10)
 RN6 = random.randint(0, 10)
 if RN1 == 0:
   PS += "0"
 elif RN1 == 1:
   PS += "1"
 elif RN1 == 2:
   PS += "2"
 elif RN1 == 3:
   PS += "3"
 elif RN1 == 4:
   PS += "4"
 elif RN1 == 5:
   PS += "5"
 elif RN1 == 6:
   PS += "6"
 elif RN1 == 7:
   PS += "7"
 elif RN1 == 8:
   PS += "8"
 elif RN1 == 9:
   PS += "9"
 elif RN2 == 0:
   PS += "0"
 elif RN2 == 1:
   PS += "1"
 elif RN2 == 2:
   PS += "2"
 elif RN2 == 3:
   PS += "3"
 elif RN2 == 4:
   PS += "4"
 elif RN2 == 5:
   PS += "5"
 elif RN2 == 6:
   PS += "6"
 elif RN2 == 7:
   PS += "7"
 elif RN2 == 8:
   PS += "8"
 elif RN2 == 9:
   PS += "9"
 if RN3 == 0:
   PS += "0"
 elif RN3 == 1:
   PS += "1"
 elif RN3 == 2:
   PS += "2"
 elif RN3 == 3:
   PS += "3"
 elif RN3 == 4:
   PS += "4"
 elif RN3 == 5:
   PS += "5"
 elif RN3 == 6:
   PS += "6"
 elif RN3 == 7:
   PS += "7"
 elif RN3 == 8:
   PS += "8"
 elif RN3 == 9:
   PS += "9"
 elif RN4 == 0:
   PS += "0"
 elif RN4 == 1:
   PS += "1"
 elif RN4 == 2:
   PS += "2"
 elif RN4 == 3:
   PS += "3"
 elif RN4 == 4:
   PS += "4"
 elif RN4 == 5:
   PS += "5"
 elif RN4 == 6:
   PS += "6"
 elif RN4 == 7:
   PS += "7"
 elif RN4 == 8:
   PS += "8"
 elif RN4 == 9:
   PS += "9"
 elif RN5 == 0:
   PS += "0"
 elif RN5 == 1:
   PS += "1"
 elif RN5 == 2:
   PS += "2"
 elif RN5 == 3:
   PS += "3"
 elif RN5 == 4:
   PS += "4"
 elif RN5 == 5:
   PS += "5"
 elif RN5 == 6:
   PS += "6"
 elif RN5 == 7:
   PS += "7"
 elif RN5 == 8:
   PS += "8"
 elif RN5 == 9:
   PS += "9"
 elif RN5 == 10:
   PS += ""
 elif RN6 == 0:
   PS += "0"
 elif RN6 == 1:
   PS += "1"
 elif RN6 == 2:
   PS += "2"
 elif RN6 == 3:
   PS += "3"
 elif RN6 == 4:
   PS += "4"
 elif RN6 == 5:
   PS += "5"
 elif RN6 == 6:
   PS += "6"
 elif RN6 == 7:
   PS += "7"
 elif RN6 == 8:
   PS += "8"
 elif RN6 == 9:
   PS += "9"
 print(PS)
 PG += 1
 PS = ""

Python版本: 3.7.4

Answer 1

让我们一步一步地检查您的代码：

首先，注意random.randint返回一个整数。因此，您需要将其转换为字符串。您可以使用str()函数将其转换为字符串，例如：

str(random.randint(0, 9))+"9"

将返回一个类似59的字符串(例如)。

因此，在初始化每个随机数时，您需要通过以下方式进行初始化，例如：

RN1 = str(random.randint(0, 9))

然后，不需要检查每个随机变量的值，只需将它们相加：

PS = RN1 + RN2 + RN3 + RN4 + RN5 + RN6

此外，您可以对前四个变量使用for循环，而不是使用六个不同的变量来处理随机值，前四个变量的值从0到9：

for x in range(4):
    RN = str(random.randint(0, 9))
    PS += RN

然后将其余两个介于0和10之间的值相加：

PS += str(random.randint(0, 10))
PS += str(random.randint(0, 10))

Answer 2

import random

# PTG = int(input("Enter the amount of pins to generate: \n"))
PTG = 10
PG = 0
PS = ""

while PTG > PG:
 RN1 = random.randint(0, 9)
 RN2 = random.randint(0, 9)
 RN3 = random.randint(0, 9)
 RN4 = random.randint(0, 9)
 RN5 = random.randint(0, 10)
 RN6 = random.randint(0, 10)

 PS = str(RN1) + str(RN2) + str(RN3) + str(RN4) + str(RN5) + str(RN6)
 print(int(PS))

 PG += 1

Answer 3

当我正确理解您的代码时，您希望生成6位数的n个引脚。你可以做的比你想做的要容易得多：

number_of_pins = int(input("Enter the amount of pins to generate: \n"))
pins = []
for i in range(number_of_pins):
    pins.append(str(random.randint(100_000, 999_999)))
print(" ".join(pins))

解释：

pins = []创建一个新的空列表来存储引脚

for i in range(n):执行下面的缩进块n次。

pins.append(random.randint(100_000, 999_999))生成一个随机数并将其添加到列表中。100000是6位数的第一个数字，999999是最后一个数字。(_只是为了可读性)。str()将其转换为字符串。

print(“".join( pins ))连接所有引脚，并在其间放置一个空格。