我有下面的表,基本上是join中的两个表。在查找Pops的关联记录时,如何删除_joinData字段?
// PopsTable.php
public function initialize(array $config)
{
parent::initialize($config);
$this->setTable('pops');
$this->setDisplayField('name');
$this->setPrimaryKey('id');
$this->belongsToMany('Menus', [
'targetForeignKey' => 'menu_id',
'foreignKey' => 'pop_id',
'joinTable' => 'pop_menus',
]);
}
// MenusTable.php
public function initialize(array $config)
{
parent::initialize($config);
$this->setTable('menus');
$this->setDisplayField('name');
$this->setPrimaryKey('id');
$this->belongsTo('Categories', [
'foreignKey' => 'category_id'
]);
$this->hasMany('MenuDetails', [
'foreignKey' => 'menu_id'
]);
$this->hasMany('Orders', [
'foreignKey' => 'menu_id'
]);
$this->belongsToMany('Pops', [
'targetForeignKey' => 'pop_id',
'foreignKey' => 'menu_id',
'joinTable' => 'pop_menus',
]);
}
// In PopsController.php
public function getAll() {
$r = $this->Pops->find('all')
->contain(['Menus' => function(Query $q) {
return $q->select(['name']);
}])
->enableHydration(false)
->enableAutoFields(false)
->formatResults(function (\Cake\Collection\CollectionInterface $results) {
return $results->each(function ($row) {
foreach ($row['menus'] as $m) {
unset($m['_joinData']); // Delete here the _joinData
}
});
});
return json_encode($r,true);
}返回数据
{
"id": 1,
"name": "umya Agropoli",
"city": "Agropoli",
"radius": 9,
"capacity": 30,
"cap": 127,
"country": "Italy",
"description": "Negozio anna 0",
"active": 1,
"book_hours_open": "1",
"book_hours_close": "1",
"menus": [
{
"name": "Base C",
"_joinData": {
"id": 1,
"pop_id": 1,
"menu_id": 2
}
}
]
}发布于 2019-12-01 01:41:45
问题出在水合作用上:如果在查询中禁用了它,formatResults似乎就不能工作了。启用水合将会起作用。实体(在本例中为Menu.php)必须包含一个隐藏变量
// in Menu.php
protected $_hidden = ['password', '_joinData'];https://stackoverflow.com/questions/59118525
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