blocks|key|989578|text|编辑:根据进一步的研究更新答案|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|989579|微分区所有权似乎确实在时间旅行窗口(在本例中为0)之后更改了所有权，因此我相信您是正确的|989580|989581|p0和p1仍归t1|unordered-list-item|989582|p2所有，p4归t3|989583|所有您的存储计算看起来是正确的，应该是17|989584|989585|请参阅Owned+Storage+vs+Referenced+Storage文档|989586|989587|与相关的：存储指标看起来不会改变，即使原始表被删除或重命名，它也会继续指向原始表。请参阅Table+Storage+Metrics+usage+notes|989588|989589|存储字节始终归最初添加字节的表所有，并因此计入该表。如果随后克隆该表，则这些初始字节的存储度量永远不会传输到克隆，即使这些字节已从源表中删除。|blockquote|989590|989591|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.snowflake.net/manuals/user-guide/tables-storage-considerations.html#owned-storage-vs-referenced-storage|1|https://docs.snowflake.net/manuals/sql-reference/account-usage/table_storage_metrics.html^0|0|F|0|0|0|0|0|0|0|3|Z|0|0|0|1|3|18|X|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1D|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|1E|8|@]|D|@]|E|$]]|$1|I|3|J|5|K|7|1F|8|@]|D|@]|E|$]]|$1|L|3|M|5|K|7|1G|8|@]|D|@]|E|$]]|$1|N|3|O|5|K|7|1H|8|@]|D|@]|E|$]]|$1|P|3|-4|5|6|7|1I|8|@]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1J|8|@]|D|@$9|1K|A|1L|1|1M]]|E|$]]|$1|S|3|-4|5|6|7|1N|8|@]|D|@]|E|$]]|$1|T|3|U|5|6|7|1O|8|@$9|1P|A|1Q|B|C]]|D|@$9|1R|A|1S|1|1T]]|E|$]]|$1|V|3|-4|5|6|7|1U|8|@]|D|@]|E|$]]|$1|W|3|X|5|Y|7|1V|8|@]|D|@]|E|$]]|$1|Z|3|-4|5|6|7|1W|8|@]|D|@]|E|$]]|$1|10|3|-4|5|6|7|1X|8|@]|D|@]|E|$]]]|11|$12|$5|13|14|15|E|$16|17]]|18|$5|13|14|15|E|$16|19]]]]

EDIT: Update answer according to further research

It does seem that micro-partition ownership does change ownership after the time-travel window (of 0 in this case) So I believe that you are correct 

<ul>
<li>p0 and p1 will still be owned by t1</li>
<li>p2 and p4 will be owned by t3</li>
<li>your storage math looks correct and should be 17</li>
</ul>

See <a href="https://docs.snowflake.net/manuals/user-guide/tables-storage-considerations.html#owned-storage-vs-referenced-storage" rel="nofollow noreferrer">Owned Storage vs Referenced Storage</a> documentation

<hr>

Related: Storage metrics don't appear to change and will continue to point at the original table even if it gets dropped or renamed.
See <a href="https://docs.snowflake.net/manuals/sql-reference/account-usage/table_storage_metrics.html" rel="nofollow noreferrer">Table Storage Metrics usage notes</a>

<blockquote>
 Storage bytes are always owned by, and therefore billed to, the table
 where the bytes were initially added. If the table is then cloned,
 storage metrics for these initial bytes never transfer to the clones,
 even if the bytes are deleted from the source table.
</blockquote>

From snowflake document <a href="http://Because%20every%20table%20within%20a%20clone%20group%20has%20an%20independent%20life-cycle,%20ownership%20of%20the%20storage%20within%20these%20tables%20sometimes%20needs%20to%20be%20transferred%20to%20a%20different%20table%20within%20the%20clone%20group.%20For%20example,%20consider%20a%20clone%20group%20that%20consists%20of:%20%20Original%20table:%20%20Cloned%20to:%20%20Cloned%20to:%20%20T1%20%20%C2%BB%20%20T2%20%20%C2%BB%20%20T3%20%20If%20T2%20and%20T3%20share%20some%20micro-partitions%20and%20T2%20is%20dropped,%20then%20ownership%20of%20that%20storage%20must%20be%20transferred%20before%20T2%20enters%20Fail-safe.%20In%20Snowflake,%20this%20transfer%20occurs%20at%20the%20time%20the%20micro-partitions%20exit%20the%20Time%20Travel%20state%20and%20would%20otherwise%20enter%20Fail-safe.%20In%20the%20case%20above,%20the%20micro-partitions%20that%20were%20previously%20owned%20by%20T2%20are%20transferred%20to%20T3%20when%20the%20Time%20Travel%20retention%20period%20expires." rel="nofollow noreferrer">clone storage usage</a>.
Every table within a clone group has an independent life-cycle, ownership of the storage within these tables sometimes needs to be transferred to a different table within the clone group. For example, consider a clone group that consists of:

<pre><code>T1 &gt;&gt; T2 &gt;&gt; T3
</code></pre>

<code>T1</code> has 10M data, <code>(p0=5M + p1=5M)</code>
<code>T1</code> and <code>T2</code> share 5M data <code>(Partition1 -&gt; p1)</code>

<code>T2</code> has 15M data, <code>(p1 + p2=5M + p3=5M)</code>
<code>T2</code> and <code>T3</code> share 10M <code>(p1 + p2)</code> data 

<code>T3</code> has 12M data, <code>(p1 + p2 + p4=2M)</code>
<code>T3</code> and <code>T2</code> share 10M data in total. <code>(p1 + p2)</code>

If the time-travel window is zero.
<code>T2</code> is dropped:

<code>p1</code> is still under <code>t1</code>'s ownership and referenced by <code>t3</code>?
<code>p2</code> ownership will be transferred from <code>t2</code> to <code>t3</code>?

And the total storage usage after <code>t2</code> is dropped is 
<code>p0 + p1 + p2 + p4 = 5 + 5 + 5 + 2 = 17</code>?

Snowflake zero copy clone billing

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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来自snowflake文档。克隆组中的每个表都有一个独立的生命周期，这些表中存储的所有权有时需要转移到克隆组中的另一个表。例如，假设一个克隆组包含以下内容：T1 >> T2 >> T3T1有1000万个数据，(p0=5M + p1=5M) T1和T2共享5M个data (Partition1 -> p1)T2有1500万个数据，(p1 + p2=5M + p3=5M) T2和T3共享1000万个(

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