我们将非常感谢您的帮助。我正在尝试从数据集中查找所有员工最近一次晋升的最后日期。数据集的示例如下所示。数据集-
mysql> select * from emp;
+----+-------+-----------+------------+
| id | empid | title | startdate |
+----+-------+-----------+------------+
| 1 | 111 | Associate | 2017-11-01 |
| 2 | 222 | ED | 2017-11-01 |
| 3 | 111 | Associate | 2017-12-01 |
| 4 | 222 | MD | 2017-12-01 |
| 5 | 111 | VP | 2018-01-01 |
| 6 | 222 | MD | 2018-01-01 |
| 7 | 111 | VP | 2018-02-01 |
| 8 | 222 | MD | 2018-02-01 |
+----+-------+-----------+------------+我想要的输出-
+-------+-----------+----------------+
| empid | title | min(startdate) |
+-------+-----------+----------------+
| 222 | MD | 2017-12-01 |
| 111 | VP | 2018-01-01 |
+-------+-----------+----------------+ 我尝试过这个SQL -
mysql> select empid, title, min(startdate)
from ( select * from emp ) x
group by title, empid
order by empid desc;它输出所有组,如下所示-
+-------+-----------+----------------+
| empid | title | min(startdate) |
+-------+-----------+----------------+
| 222 | MD | 2017-12-01 |
| 222 | ED | 2017-11-01 |
| 111 | Associate | 2017-11-01 |
| 111 | VP | 2018-01-01 |
+-------+-----------+----------------+发布于 2019-12-05 05:04:05
只接受empid和max(startdate)作为子查询,并将其连接回主表:
SELECT *
FROM emp e
INNER JOIN
(SELECT empid, Max(startdate) recentpromo FROM emp GROUP BY empid) x
ON x.empid = e.empid AND x.recentpromo = e.startdate如果你使用的是mysql8,你可以使用ROW_NUMBER作为替代。如果一名员工在同一天被提升了两次,那么这两个记录都会出现,不过我认为这种情况不太可能发生
编辑,因此我们可以将其扩展到另一个级别:
SELECT
em.empid,
em.title,
min(em.startdate) as
FROM
emp em
INNER JOIN
(
SELECT e.empid, e.title
FROM emp e
INNER JOIN
(SELECT empid, Max(startdate) recentpromo FROM emp GROUP BY empid) x
ON x.empid = e.empid AND x.recentpromo = e.startdate
) frpt --find recent promo title
ON
em.empid = frpt.empid AND
em.title = frpt.title
GROUP BY
em.empid, em.titlehttps://stackoverflow.com/questions/59184607
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