Rasa超时问题

Question

当运行Rasa (在版本1.3.3，1.3.7，1.3.8上尝试)时，我几乎每次调用时都会遇到此超时异常消息。我正在运行一个简单的程序，它可以识别用户何时提供他们的年龄，并通过操作响应将年龄存储在数据库中：

Bot loaded. Type a message and press enter (use '/stop' to exit):
Your input ->  I am 24 years old
2019-10-10 13:29:33 ERROR    asyncio  - Task exception was never retrieved
future: <Task finished coro=<configure_app.<locals>.run_cmdline_io() done, defined at /Users/Kami/Documents/rasa/venv/lib/python3.7/site-packages/rasa/core/run.py:123> exception=TimeoutError()>
Traceback (most recent call last):
  File "/Users/Kami/Documents/rasa/venv/lib/python3.7/site-packages/rasa/core/run.py", line 127, in run_cmdline_io
    server_url=constants.DEFAULT_SERVER_FORMAT.format("http", port)
  File "/Users/Kami/Documents/rasa/venv/lib/python3.7/site-packages/rasa/core/channels/console.py", line 138, in record_messages
    async for response in bot_responses:
  File "/Users/Kami/Documents/rasa/venv/lib/python3.7/site-packages/async_generator/_impl.py", line 366, in step
    return await ANextIter(self._it, start_fn, *args)
  File "/Users/Kami/Documents/rasa/venv/lib/python3.7/site-packages/async_generator/_impl.py", line 205, in throw
    return self._invoke(self._it.throw, type, value, traceback)
  File "/Users/Kami/Documents/rasa/venv/lib/python3.7/site-packages/async_generator/_impl.py", line 209, in _invoke
    result = fn(*args)
  File "/Users/Kami/Documents/rasa/venv/lib/python3.7/site-packages/rasa/core/channels/console.py", line 103, in send_message_receive_stream
    async for line in resp.content:
  File "/Users/Kami/Documents/rasa/venv/lib/python3.7/site-packages/aiohttp/streams.py", line 40, in __anext__
    rv = await self.read_func()
  File "/Users/Kami/Documents/rasa/venv/lib/python3.7/site-packages/aiohttp/streams.py", line 329, in readline
    await self._wait('readline')
  File "/Users/Kami/Documents/rasa/venv/lib/python3.7/site-packages/aiohttp/streams.py", line 297, in _wait
    await waiter
  File "/Users/Kami/Documents/rasa/venv/lib/python3.7/site-packages/aiohttp/helpers.py", line 585, in __exit__
    raise asyncio.TimeoutError from None
concurrent.futures._base.TimeoutError
Transport closed @ ('127.0.0.1', 63319) and exception experienced during error handling

最初我认为这个超时是由我的Rasa程序的另一部分使用大型查找表引起的，但为了识别年龄，我使用了一个简单的正则表达式：

## regex:age
- ^(0?[1-9]|[1-9][0-9]|[1][1-9][1-9])$

即使这样也会导致超时。

请帮我解决这个问题。我甚至不需要避免超时，我只想知道在哪里可以捕获/忽略这个异常。

谢谢!

Answer 1

确保取消对以下代码的注释

action_endpoint:
 url: "http://localhost:5055/webhook"

在endpoints.yml中。当您进行自定义操作以查询数据库时，将使用它。

Answer 2

我从一个API获取数据，其中我得到一个超时错误，因为它无法在默认时间限制内获取数据：

转到该目录: venv/Lib/site-packages/rasa/core/channels/console.py

• Change将DEFAULT_STREAM_READING_TIMEOUT_IN_SECONDS的默认值设置为大于10，在我的示例中，我将其更改为30，它起作用了。

另一个原因可能是在短时间内一次又一次地获取数据，这可能导致超时。

观察值:

DEFAULT_STREAM_READING_TIMEOUT_IN_SECONDS设置为10时出现超时错误DEFAULT_STREAM_READING_TIMEOUT_IN_SECONDS设置为30时出现超时错误

• 一次又一次地运行rasa shell时出现超时错误

• DEFAULT_STREAM_READING_TIMEOUT_IN_SECONDS设置为30且运行rasa shell的频率不高它工作正常。

Answer 3

我现在不能评论，但请在Vishal回复中添加后续内容。要检查挂钩是否存在并等待连接，可以使用-vv命令行开关。这将在启动时显示所有可用挂钩。例如：

2020-04-21 14:05:56 DEBUG    rasa.core.utils  - Available web server routes:
/webhooks/rasa                                     GET                            custom_webhook_RasaChatInput.health
/webhooks/rasa/webhook                             POST                           custom_webhook_RasaChatInput.receive
/webhooks/rest                                     GET                            custom_webhook_RestInput.health
/webhooks/rest/webhook                             POST                           custom_webhook_RestInput.receive
/                                                  GET                            hello