当提交按钮在另一个html文件中时运行php文件

Question

我想在注册过程中工作，在谷歌和Youtube的帮助下，我已经创建了“登录和唱歌”页面与切换选项，但无法运行registration.php文件一旦用户提供注册信息在login.html文件。代码如下：

<form id="login" class="input-group">
    <input type="text" class="input-field" placeholder="User Id" required>
    <input type="password" class="input-field" placeholder="Enter Password" required>
    <input type="checkbox" class="check-box"><span>Remember Password</span>
    <button type="submit" class="submit-btn">Sign-In</button>
</form>

<form Id="register" class="input-group">
    <input type="text" class="input-field" placeholder="User Id" required>
    <input type="email" class="input-field" placeholder="Email Id" required>
    <input type="password" class="input-field" placeholder="Enter Password" required>
    <input type="password" class="input-field" placeholder="Confirm Password" required>
    <input type="phone-number" class="input-field" placeholder="Mobile Number" required>
    <input type="checkbox" class="check-box"><span>I agree to the terms & conditions</span>
    <button type="submit" class="submit-btn">Sign-Up</button>
</form>

如何在login.html文件中点击注册按钮执行registration.php文件？登录选项也是如此。

Answer 1

method属性指定如何发送表单数据(表单数据被发送到action属性中指定的页面)。

表单数据可以作为URL变量(使用method="get")或HTTP post事务(使用method="post")发送。

请查看此处了解更多详细信息w3schools

<form id="login" class="input-group" method="POST" action="file_path/login.php">
    <input type="text" class="input-field" placeholder="User Id" required>
    <input type="password" class="input-field" placeholder="Enter Password" required>
    <input type="checkbox" class="check-box"><span>Remember Password</span>
    <input type="submit" class="submit-btn" value="Sign-In">
</form>

<form Id="register" class="input-group" method="POST" action="file_path/register.php">
    <input type="text" class="input-field" placeholder="User Id" required>
    <input type="email" class="input-field" placeholder="Email Id" required>
    <input type="password" class="input-field" placeholder="Enter Password" required>
    <input type="password" class="input-field" placeholder="Confirm Password" required>
    <input type="phone-number" class="input-field" placeholder="Mobile Number" required>
    <input type="checkbox" class="check-box"><span>I agree to the terms & conditions</span>
    <input type="submit" class="submit-btn" value="Sign-Up">
</form>

根据您的评论进行编辑

将按钮替换为输入type="submit“，并将@放在php变量前，这样就不会收到未定义的错误通知(@用于避免错误通知)

<div class="header"> 
    <h2>Register here</h2> 
</div> 
<form method="post" action="register.php"> 
    <?php include('errors.php'); ?> 
    <div class="input-group"> 
        <label>Username</label> 
        <input type="text" name="username" value="<?php echo @$username; ?>"> 
    </div> 
    <div class="input-group"> 
            <label>Email</label> 
            <input type="email" name="email" value="<?php echo @$email; ?>"> 
        </div> 
        <div class="input-group"> 
            <label>Password</label> 
            <input type="password" name="password_1"> 
        </div> 
        <div class="input-group"> 
            <label>Confirm Password</label> 
            <input type="password" name="password_2"> 
        </div>


<div class="input-group"> 
    <label>Mobile number</label> 
    <input type="number" name="mobile" value="<?php echo @$mobile; ?>"> 
</div> 
<div class="input-group"> 
    <input type="submit" class="btn" name="reg_user" value="Sign-Up">
</div> 
</form>

在register.php中创建register.php文件

<?php
$con = mysqli_connect("localhost", "username", "password", "dbname") or trigger_error("Unable to connect to the database");
    if(isset($_POST['reg_user'])){
        $name = $_POST['username']; //here "username" is what you defined in the "name" field of input form
    //define other variables
        //write your own sql query , here is an example
        $query = "INSERT INTO table(name) VALUES(?)";
        $stmt = mysqli_stmt_init($con);
        if(!mysqli_stmt_prepare($stmt,$query)){
            echo "Error";
        }else{
            mysqli_stmt_bind_param($stmt,"s",$name);
            mysqli_stmt_execute($stmt);
        }
    }
?>

Answer 2

确保在表单中添加method="POST"、action="path/function.php"和name="desiredName"，如下所示：

<form id="login" class="input-group" method="POST" action="file_path/login.php">
    <input type="text" class="input-field" placeholder="User Id" name ="user" required>
    <input type="password" class="input-field" placeholder="Enter Password" name="password" required>
    <input type="checkbox" class="check-box"><span>Remember Password</span>
    <button type="submit" class="submit-btn">Sign-In</button>
</form>

然后在PHP中，为了“捕捉”post中的数据，您将使用如下代码：

$this->getpost['user'];

或

$_POST['user'];