我觉得我做的都错了。Typescript试图告诉我要做什么?我在这里玩变态游戏
TypeScript error in /Users/alex-wilmer/Projects/resideo/pro-portal/packages/web/src/utils/feature-flags/index.tsx(46,9):
Type 'Dispatch<SetStateAction<{ OCT19_DEMO: undefined; }>>' is not assignable to type '() => void'. TS2322
44 | value={{
45 | flags,
> 46 | setFlags,
| ^
47 | }}>
48 | {children}
49 | </FeatureFlagsContext.Provider>import React, {
createContext,
useContext,
FC,
useState,
Dispatch,
SetStateAction,
} from 'react';
type Flags = {
OCT19_DEMO: string | undefined;
};
type UseFeatureFlagsValue = {
flags: Flags;
setFlags: Dispatch<SetStateAction<{}>>;
};
export const FeatureFlagsContext = createContext({
flags: { OCT19_DEMO: undefined },
setFlags: () => {},
});
export const FEATURE_FLAG_PREFIX = 'REACT_APP_FEATURE_FLAG_';
export const FeatureFlagsProvider: FC<{
children: React.ReactNode;
}> = ({ children }): JSX.Element => {
const [flags, setFlags] = useState(
Object.entries(process.env).reduce(
(acc, [key, val]) => {
if (!key.startsWith(FEATURE_FLAG_PREFIX)) return acc;
acc[key.replace(FEATURE_FLAG_PREFIX, '')] = val;
return acc;
},
{
OCT19_DEMO: undefined,
}
)
);
return (
<FeatureFlagsContext.Provider
value={{
flags,
setFlags,
}}>
{children}
</FeatureFlagsContext.Provider>
);
};
export const useFeatureFlags = (): UseFeatureFlagsValue =>
useContext(FeatureFlagsContext);发布于 2019-10-16 10:42:49
createContext接受一个类型参数,所以传入类型UseFeatureFlagsValue可以解决这个问题:
export const FeatureFlagsContext = createContext<UseFeatureFlagsValue>({
flags: { OCT19_DEMO: undefined },
setFlags: () => {},
});您是否需要在此处使用默认值?大多数情况下,在创建上下文时,您不应该需要传递默认值(理想情况下,您的使用者应该在可以提供有用内容的提供者中呈现)。
仅当组件在树中的上方没有匹配的提供程序时,才使用defaultValue参数。这对于在不包装组件的情况下隔离测试组件非常有用。注意:将undefined作为Provider值传递不会导致使用组件使用defaultValue。
如果不需要使用默认值,则可以使用Non-Null assertion operator通过undefined创建上下文
export const FeatureFlagsContext = createContext<UseFeatureFlagsValue>(undefined!);https://stackoverflow.com/questions/58404182
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