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社区首页 >问答首页 >这段代码对于使用Arduino Uno生成正弦波是否有效/合理?

这段代码对于使用Arduino Uno生成正弦波是否有效/合理?
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Stack Overflow用户
提问于 2019-09-11 00:50:12
回答 1查看 633关注 0票数 0

注意:我省略了其他两个阶段(V和W)的代码,对于示例来说不是必需的。

我非常确定,像这样处理“开”和“关”的方式并不是一种有效的方式。

我想使用查找表来实现“开”和“关”的脉动。计时器应与表格的当前选定值进行比较,如果该值通过,则切换输出。

问题:我认为我对计时器的处理“错误”。我没有得到正确数量的脉冲(我的理解是,我应该得到与数组中的值一样多的脉冲,在本例中是300+)。看着示波器,我注意到只有几个脉冲。

我使用“输出比较寄存器”会更好吗?

你还有什么其他的建议/想法吗?

代码语言:javascript
复制
bool posTOneg = true;               // Variable for the change from positive to negative. 'true' in the beginning.

///// CONFIGURATION OF THE PINS /////

int igbt_high_u = 11;
int igbt_high_v = 10;
int igbt_high_w = 9;

int igbt_low_u = 6;
int igbt_low_v = 5;
int igbt_low_w = 3;

///// LOOKUP TABLE /////
int UsinPWM[]={1,2,5,7,10,12,15,17,19,22,24,27,30,32,34,37,39,42,
44,47,49,52,54,57,59,61,64,66,69,71,73,76,78,80,83,85,88,90,92,94,97,99,                                      //42 Werte bis hier hin
101,103,106,108,110,113,115,117,119,121,124,126,128,130,132,134,136,138,140,142,144,146,
148,150,152,154,156,158,160,162,164,166,168,169,171,173,175,177,178,180,182,184,185,187,188,190,192,193,      // 90
195,196,198,199,201,202,204,205,207,208,209,211,212,213,215,216,217,219,220,221,222,223,224,225,226,227,
228,229,230,231,232,233,234,235,236,237,237,238,239,240,240,241,242,242,243,243,244,244,245,245,246,246,      // 142
247,247,247,248,248,248,248,249,249,249,249,249,250,250,250,250,249,249,249,249,249,248,
248,248,248,247,247,247,246,246,245,245,244,244,243,243,242,242,241,240,240,239,238,237,237,236,235,234,      // 190
233,232,231,230,229,228,227,226,225,224,223,222,221,220,219,217,216,215,213,212,211,209,208,207,205,204,
202,201,199,198,196,195,193,192,190,188,187,185,184,182,180,178,177,175,173,171,169,168,166,164,162,160,      // 242
158,156,154,152,150,148,146,144,142,140,138,136,134,132,130,128,126,124,121,119,117,115,113,110,108,106,
103,101,99,97,94,92,90,88,85,83,80,78,76,73,71,69,66,64,61,59,57,54,52,49,47,44,42,39,37,34,32,30,            // 300
27,24,22,19,17,15,12,10,7,5,2,1};                                                                             // 312

///// SIZE OF THE ARRAY /////
int sizeU = sizeof(UsinPWM)/sizeof(int);      // Variable for PWM array (size)
///// OFFSET 120 GRAD /////
int indexU = 0;              // zaehlervariable

///// FUNCTION FOR THE PHASE U (POS AND NEG HALF-CYCLE) /////
void posHalbU (int i)
{
  if(TCNT0 < UsinPWM[i])                              // Compare timer with the current value of the look up table
  {
    digitalWrite(igbt_low_v, HIGH);                   // Triggering hardware
    digitalWrite(igbt_low_w, HIGH);
    digitalWrite(igbt_high_u, HIGH);
  }
  else
  {
    digitalWrite(igbt_high_u, LOW);
    digitalWrite(igbt_low_v, LOW);
    digitalWrite(igbt_low_w, LOW);
  }
}

void negHalbU(int i)
{
  if(TCNT0 < UsinPWM[i])
  {
    digitalWrite(igbt_high_v, HIGH);
    digitalWrite(igbt_high_w, HIGH);
    digitalWrite(igbt_low_u, HIGH);
  }
  else
  {
    digitalWrite(igbt_high_v, LOW);
    digitalWrite(igbt_high_w, LOW);
    digitalWrite(igbt_low_u, LOW);
  }
}


void setup()
{
  Serial.begin(9600);

  ///// CONFIGURE PWM /////
  pinMode(igbt_high_u, OUTPUT);
  pinMode(igbt_high_v, OUTPUT);
  pinMode(igbt_high_w, OUTPUT);
  pinMode(igbt_low_u, OUTPUT);
  pinMode(igbt_low_v, OUTPUT);
  pinMode(igbt_low_w, OUTPUT);
}

void loop()
{
  ///// CALL PHASE U  /////
  if(posTOneg)
  {
    posHalbU(indexU);
  }
  else
  {
    negHalbU(indexU);
  }


  indexU = indexU + 1;

  if(indexU == sizeU)
  {
    indexU = 0;                             // Reset of the counter variable
    posTOneg = !posTOneg;                   // Negate the boolean value. Swapping between pos and neg all the time
  }
}

下面是我生成的结果。大约产生了20个脉冲,并且这些脉冲是周期性地产生的。

EN

回答 1

Stack Overflow用户

发布于 2019-09-11 00:58:24

使用for loop在正弦数组中自动编制索引。以指定的时间间隔使用analogWrite()将数据写入脉宽调制引脚。时间间隔x数组大小=正弦周期。

输出看起来会很糟糕。这只是一个快速变化的脉宽调制信号,伸展范围为0-5 V。经过适当的滤波后,一个正弦波将神奇地出现。

票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/57875203

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