我使用ant设计表,并使用getColumnSearchProps进行column-driven搜索。我希望将search input放在列的标题中。但是我不知道如何处理对此列和输入的搜索?
数据:
const data = [
{
key: '1',
name: 'John Brown',
age: 32,
address: 'New York No. 1 Lake Park',
},
{
key: '2',
name: 'Joe Black',
age: 42,
address: 'London No. 1 Lake Park',
}]以下是我的专栏:
const columns = [
{
title: (
<>
<Search
placeholder="search"
prefix={<CPIcon type="search" />}
onChange={??????????????}
/>
name
</>
),
dataIndex: 'name',
key: '1',
align: 'right',
render: text => (<h1>{text}</h1>)
},
other columns ...
]在render中:
<Table columns={columns} dataSource={data} />发布于 2019-08-13 16:17:21
在String.includes()中使用Array.filter()
另外,请注意,Input.Search只添加了两个属性:onSearch和enterButton,因此不使用任何额外的道具来呈现它是没有意义的。
export default function App() {
const [dataSource, setDataSource] = useState(data);
const [value, setValue] = useState('');
const FilterByNameInput = (
<Input
placeholder="Search Name"
value={value}
onChange={e => {
const currValue = e.target.value;
setValue(currValue);
const filteredData = data.filter(entry =>
entry.name.includes(currValue)
);
setDataSource(filteredData);
}}
/>
);
const columns = [
{
title: FilterByNameInput,
dataIndex: 'name',
key: '1'
}
];
return (
<FlexBox>
<Table columns={columns} dataSource={dataSource} />
</FlexBox>
);
}
发布于 2020-08-11 10:30:35
另一个答案真的有效吗?我实际上使用了一个额外的useCallback函数:
export default () => {
const [data, setData] = useState(null)
const [val, setVal] = useState('')
const filterVals = useCallback((e) => {
const currValue = e.target.value
setVal(currValue)
const filteredVals = data.filter(entry =>
entry.val.includes(currValue)
)
setData(filteredVals)
}, [loading])
const columns = [
{
title:
<Input
placeholder="lalaland"
value={val}
onChange={filterVals}
/>,
dataIndex: 'val',
},
]
return (
<Table
bordered
dataSource={data}
columns={columns}
/>
)
}https://stackoverflow.com/questions/57471984
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