如何通过脚本从adword活动中排除多个邮政编码？

Question

我在谷歌AdWords中遇到了问题。我想排除邮政编码从所有活动通过脚本，脚本适用于帐户上的所有活动

    function main() {
  excludeLocationTarget();
}
function excludeLocationTarget() {
  var campaignIterator = AdsApp.campaigns()
      .withCondition('Name = "US-WooCommerce"')
      .get();
  if (campaignIterator.hasNext()) {
    var campaign = campaignIterator.next();
    // Exclude Tennessee, United States (location id = 21175) See
    // https://developers.google.com/adwords/api/docs/appendix/geotargeting
    // for list of all supported geo codes.
    // You could pass either the location code, or a TargetedLocation or
    // ExcludedLocation object from an existing campaign.
    var tennessee_id =['21175','21176'];
    for(val in tennessee_id){
      Logger.log(tennessee_id[val]);
      campaign.excludeLocation(tennessee_id[val]);
    }

  }
}

2019年7月31日11:45:44 PM 21175 2019-07-31 11:45:44 PM无效参数: id。类型应为: number (文件Code.gs，第19行)

Answer 1

excludeLocation方法需要一个整数参数，而您使用的是字符串。这就是excludeLocation失败的原因。试一试

var tennessee_id =[21175,21176]; // numerical values instead of strings
    for(val in tennessee_id){
      Logger.log(tennessee_id[val]);
      campaign.excludeLocation(tennessee_id[val]);
    }

或campaign.excludeLocation(parseInt(tennessee_id[val]));