使用Scrapy提取数据，但在使用css.seletor时遇到问题

Question

我想不出怎么才能拿到标题。

response.css('.goods_property_color a.current').extract()

  <p id="select-attr-0" class="attr-choose clearfix goods_property_color" data-type="Color"> <span class="property-title">Color</span>      <a href="javascript:void(0)" class="itemAttr current -sitemap-select-item-selected" title="WHITE" data-value="WHITE"><img src="https://gloimg.rglcdn.com/rosegal/pdm-product-pic/Clothing/2019/04/08thumb-img/1554676715239391822.jpg" class=""></a> 

我想要的只是“白色”

但我得到的是：

['a href="javascript:void(0)" class="itemAttr current " title="WHITE" data-value="WHITE"> src=h://gloimg.rglcdn.com/rosegal/pdm-product-pic/Clothing/2019/04/08thumb-img/1554676715239391822.j"></a>']

Answer 1

response.css('.goods_property_color a.current::attr(data-value)').get()

或

response.css('.goods_property_color a.current::attr(title)').get()