flutter套接字:当我在Flutter中多次使用socket.listen()时，如何获得异步重启？

Question

为什么我拿不到listen2的结果？如何修改？在示例中，我只能访问listen1结果，而不能访问listen2结果。我是新来的

sample code:

  Future<List<int>> getResult() async {
    var a =  creatDataToken();
    var e=  await Socket.connect(MyApp.host, MyApp.port).then((Socket socket) async{
        socket.add(a);
        socket.listen((List<int> listen1) async{
          debugPrint('result listen1 :$listen1');
          List<int> loginList=  creatDataLogin(listen1);
          await  Socket.connect(MyApp.host, MyApp.port).then((Socket socket) async {
                    socket.add(loginList);
                    debugPrint('add:$loginList');
                    await socket.listen((List<int> listen2) {
                      debugPrint('result listen2 :$listen2');
                        return listen2;
                    });
              });
        });
    });

enter image description here

Answer 1

 bool flag;
  Future getResult() async {
    flag = false;
   var a =  creatDataToken() ;
   var b= await Socket.connect(MyApp.host, MyApp.port).then((Socket socket){
          mSocket=socket;
          mSocket.add(a);
          mSocket.addError((e){debugPrint('---addError--$e');});
          mSocket.listen(onReceiver);
    }).catchError((error){
             debugPrint('---catchError--$error');
              ToastUtils.showShortToast('username or password error!');
              return;
           });
    return b;
  }

  void onReceiver(List<int> event) {
    if(!flag){
      debugPrint('result listen1 :$event');
      flag=true;
      List<int> loginList=  creatDataLogin(event);
      debugPrint('loginList:$loginList');
      mSocket.add(loginList);
    }else{
      debugPrint('result listen2 :$event');
      resolveResult(event);
    }
  }