跨react-table实现全局搜索过滤器: React+ react-table

Question

我正在尝试实现一个全局搜索过滤器，它可以在整个表中搜索关键字。我附加了一个更改处理程序，并且在每个输入上都触发了一个回调，该回调在整个数据中搜索关键字，值在我键入字符时被过滤-但是我希望当我在搜索输入中输入多个搜索值(如string1，string2 )时，搜索能够正常工作

代码沙盒：https://codesandbox.io/s/jolly-bhabha-iqcx1

代码

import React from "react";
import ReactDOM from "react-dom";
import { Input } from "semantic-ui-react";
import ReactTable from "react-table";
import "react-table/react-table.css";
import "./styles.css";

export default class App extends React.Component {
  constructor(props) {
    super(props);
    this.state = {
      data: [
        { firstName: "aaaaa", status: "Pending", visits: 155 },
        { firstName: "aabFaa", status: "Pending", visits: 155 },
        { firstName: "adaAAaaa", status: "Approved", visits: 1785 },
        { firstName: "aAaaaa", status: "Approved", visits: 175 },
        { firstName: "adaSaaa", status: "Cancelled", visits: 165 },
        { firstName: "aasaaa", status: "Cancelled", visits: 157 },
        { firstName: "aweaaaaaewea", status: "Approved", visits: 153 },
        { firstName: "aaaaaa", status: "Submitted", visits: 155 }
      ],
      columns: [],
      searchInput: ""
    };
  }

  componentDidMount() {
    let columns = [
      {
        Header: "First Name",
        accessor: "firstName",
        sortable: false,
        show: true,
        displayValue: " First Name"
      },
      {
        Header: "Status",
        accessor: "status",
        sortable: false,
        show: true,
        displayValue: "Status "
      },
      {
        Header: "Visits",
        accessor: "visits",
        sortable: false,
        show: true,
        displayValue: " Visits "
      }
    ];
    this.setState({ columns });
  }

  handleChange = event => {
    this.setState({ searchInput: event.target.value }, () => {
      this.globalSearch();
    });
  };

  globalSearch = () => {
    let { data, searchInput } = this.state;
    if (searchInput) {
      let filteredData = data.filter(value => {
        return (
          value.firstName.toLowerCase().includes(searchInput.toLowerCase()) ||
          value.status.toLowerCase().includes(searchInput.toLowerCase()) ||
          value.visits
            .toString()
            .toLowerCase()
            .includes(searchInput.toLowerCase())
        );
      });
      this.setState({ data: filteredData });
    }
  };

  render() {
    let { data, columns, searchInput } = this.state;
    return (
      <div>
        <br />
        <Input
          size="large"
          name="searchInput"
          value={searchInput || ""}
          onChange={this.handleChange}
          label="Search"
        />
        <br />
        <br />
        <ReactTable
          data={data}
          columns={columns}
          defaultPageSize={10}
          className="-striped -highlight"
        />
      </div>
    );
  }
}

const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);

Answer 1

这不是react-table的问题。在当前的实现中，

1. 第一次，你可以从原始数据中进行过滤。
2. 第二次尝试筛选时，您是在尝试从先前筛选的数据中筛选结果(状态对象中的当前数据是上次尝试的筛选结果)。

我建议尝试一下(这是从你的派生的)：https://codesandbox.io/s/eloquent-clarke-w1ehv

将原始数据作为不可变源进行维护，并在每次更改搜索输入时从中进行过滤，而不是从状态中的当前数据对象进行过滤。看一下我连接的叉子。

如果数据来自ajax调用，则可能需要维护两个状态变量：

this.state = {
   data: [],
   filteredData: [],
   columns: [],
   searchInput: ""
};

componentDidMount() {
  yourapicall.then(data => {
    this.setState({
      data // whatever data you get.
    });
  });
}

// And in your global search

globalSearch = () => {
    let { searchInput, data } = this.state;
    let filteredData = data.filter(value => {
    return (
        value.firstName.toLowerCase().includes(searchInput.toLowerCase()) ||
        value.status.toLowerCase().includes(searchInput.toLowerCase()) ||
        value.visits
          .toString()
          .toLowerCase()
          .includes(searchInput.toLowerCase())
      );
    });
    this.setState({ filteredData });
};

并有条件地呈现您的反应表

<ReactTable
   data={filteredData && filteredData.length ? filteredData : data}
   columns={columns}
   defaultPageSize={10}
   className="-striped -highlight"
/>

希望这能对你有所帮助！