我有一个PHP脚本,查询的是表中每个用户的特定行数。然后,我让SQL查询使用"AS“来输出每个用户各自的计数;如下所示:
<?php
$servername = "localhost";
$username = "name";
$password = "mypassword";
$dbname = "mydatabase";
//Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
//Check connection
if($conn->connect_error) {
die("Connection failed:" . $conn->connect_error);
}
$sql = "SELECT SUM(answer LIKE '%Author: Charlotte Augustine%') AS Charlotte_Posts,SUM(answer LIKE '%Author: Jason Biskie%') AS Biskie_Posts,
SUM(answer LIKE '%Author: Chris Borie%') AS Borie_Posts,
SUM(answer LIKE '%Author: Jason Burton%') AS Burton_Posts,
SUM(answer LIKE '%Author: Marcus Jackman%') AS Jackman_Posts,
SUM(answer LIKE '%Author: Karl Kreder%') AS Kreder_Posts,
SUM(answer LIKE '%Author: Quezada%') AS Quezada_Posts,
SUM(answer LIKE '%Author: Chris Roland%') AS Roland_Posts,
SUM(answer LIKE '%Author: Patrick Shafer%') AS Shafer_Posts,
SUM(answer LIKE '%Author: Patrick Tokeshi%') AS Tokeshi_Posts,
SUM(answer LIKE '%Author: Jonathan Vasquez%') AS Vasquez_Posts
FROM `ost_faq` WHERE created >= curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY into outfile '/var/lib/mysql-files/posts.txt'";
if (mysqli_query($conn, $sql)) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . mysqli_error($conn);
}
mysqli_close($conn);
?>现在,如果我在MySQL命令行运行这个查询,我会得到以下输出:
+-----------------+--------------+-------------+--------------+---------------+--------------+---------------+--------------+--------------+---------------+---------------+
| Charlotte_Posts | Biskie_Posts | Borie_Posts | Burton_Posts | Jackman_Posts | Kreder_Posts | Quezada_Posts | Roland_Posts | Shafer_Posts | Tokeshi_Posts | Vasquez_Posts |
+-----------------+--------------+-------------+--------------+---------------+--------------+---------------+--------------+--------------+---------------+---------------+
| 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 2 | 0 |
+-----------------+--------------+-------------+--------------+---------------+--------------+---------------+--------------+--------------+---------------+---------------+但是,当我检查我的输出文件"posts.txt“时,它只有数字,如下所示:
0 0 0 0 1 0 0 0 0 2 0我需要将这些数据输出到文本文件中,因为我会将文本文件转换为每周自动发送给自己的电子邮件。
为什么名称不能输出到文本文件?有没有办法输出"AS“字符串?
我不知道是不是我的自动邮件bash脚本导致了这个问题。如果是,下面是脚本:
#!/bin/bash
echo "Weekly Stats" > posts.txt
echo "=============================" >> posts.txt
cat "/var/lib/mysql-files/posts.txt" >> posts.txt
if [ -s /var/lib/mysql-files/posts.txt ]
then
cat "posts.txt" | mail -s "Stats" me@domain.com
rm -f /var/lib/mysql-files/posts.txt
else
echo "No Stats Available." | mail -s "No Stats" me@domain.com
rm -f /var/lib/mysql-files/posts.txt
fi提前谢谢你。
发布于 2019-05-11 03:43:23
不幸的是,在outfile中包含字段名作为标头的唯一方法是在查询中硬编码标头(请参阅此question/answer):
$sql = "
SELECT 'Charlotte_Posts',
'Biskie_Posts' ,
'Borie_Posts' ,
'Burton_Posts' ,
'Jackman_Posts' ,
'Kreder_Posts' ,
'Quezada_Posts' ,
'Roland_Posts' ,
'Shafer_Posts' ,
'Tokeshi_Posts' ,
'Vasquez_Posts'
UNION ALL
SELECT SUM(answer LIKE '%Author: Charlotte Augustine%') AS Charlotte_Posts,
SUM(answer LIKE '%Author: Jason Biskie%') AS Biskie_Posts,
SUM(answer LIKE '%Author: Chris Borie%') AS Borie_Posts,
SUM(answer LIKE '%Author: Jason Burton%') AS Burton_Posts,
SUM(answer LIKE '%Author: Marcus Jackman%') AS Jackman_Posts,
SUM(answer LIKE '%Author: Karl Kreder%') AS Kreder_Posts,
SUM(answer LIKE '%Author: Quezada%') AS Quezada_Posts,
SUM(answer LIKE '%Author: Chris Roland%') AS Roland_Posts,
SUM(answer LIKE '%Author: Patrick Shafer%') AS Shafer_Posts,
SUM(answer LIKE '%Author: Patrick Tokeshi%') AS Tokeshi_Posts,
SUM(answer LIKE '%Author: Jonathan Vasquez%') AS Vasquez_Posts
FROM `ost_faq` WHERE created >= curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY
INTO OUTFILE '/var/lib/mysql-files/posts.txt'";在您的上下文中,与MySQL创建输出文件相比,将MySQL结果从PHP输出到文本文件可能是最简单的。可以在here中找到如何从MySQL查询的数组结果创建这样一个文件的示例。
https://stackoverflow.com/questions/56083463
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