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社区首页 >问答首页 >如何在“连接(提供者)”问题(ReactJs,Redux,SimpleWebRTC)的上下文或道具中修复“找不到”存储?

如何在“连接(提供者)”问题(ReactJs,Redux,SimpleWebRTC)的上下文或道具中修复“找不到”存储?
EN

Stack Overflow用户
提问于 2019-05-11 02:50:52
回答 1查看 260关注 0票数 1

我正在尝试从这里启动SimpleWebRTC应用程序:https://docs.simplewebrtc.com/#/?id=getting-started

App.js文件:

代码语言:javascript
复制
import React from "react";
import { Provider } from "react-redux";
import ReduxToastr from "react-redux-toastr";
import store from "./redux/store/index";
import Routes from "./routes/Routes";

const App = () => (
  <Provider store={store}>
    <Routes />
    <ReduxToastr
      timeOut={5000}
      newestOnTop={true}
      position="top-right"
      transitionIn="fadeIn"
      transitionOut="fadeOut"
      progressBar
      closeOnToastrClick
    />
  </Provider>
);

export default App;

./redux/store/index.js文件:

代码语言:javascript
复制
import { combineReducers } from "redux";

import sidebar from "./sidebarReducers";
import layout from "./layoutReducer";
import theme from "./themeReducer";
import app from "./appReducer";
import auth from "./authReducer";
import { reducer as simplewebrtc } from '@andyet/simplewebrtc';
import { reducer as toastr } from "react-redux-toastr";

export default combineReducers({
  sidebar,
  layout,
  theme,
  toastr,
  app,
  auth,
  simplewebrtc
});

./redux/store/index.js文件:

代码语言:javascript
复制
import { createStore, applyMiddleware } from "redux";
import thunk from 'redux-thunk';
import rootReducer from "../reducers/index";

const persistedState = localStorage.getItem('reduxState') ? JSON.parse(localStorage.getItem('reduxState')) : {}

var store

if(persistedState.app){
    store = createStore(rootReducer, persistedState, applyMiddleware(thunk));
}else{  
    store = createStore(rootReducer, applyMiddleware(thunk));
}

store.subscribe(()=>{
    localStorage.setItem('reduxState', JSON.stringify(store.getState()))
})


export default store;

Chat.js文件:

代码语言:javascript
复制
const API_KEY = '';
const ROOM_PASSWORD = 'test';
const CONFIG_URL = `https://api.simplewebrtc.com/config/guest/${API_KEY}`
const ROOM_NAME = 'uniq-room-name'

class _SimpleWebRtc extends React.Component {

  constructor(props) {
    super(props);
  }

  render(){


    return (
        <SWRTC.Provider configUrl={CONFIG_URL}>      {/* <------- problem here */}
          {/* Render based on the connection state */}
          <SWRTC.Connecting>
            <h1>Connecting...</h1>
          </SWRTC.Connecting>

          <SWRTC.Connected>
            <h1>Connected!</h1>

            <SWRTC.RequestUserMedia audio auto />

            <SWRTC.Room name={ROOM_NAME} password={ROOM_PASSWORD}>
              <SWRTC.RemoteAudioPlayer />
            </SWRTC.Room>

          </SWRTC.Connected>
        </SWRTC.Provider>
    )
  }
}

const SimpleWebRtc = connect(store => ({simplewebrtc: store.simplewebrtc})) (_SimpleWebRtc)

当我尝试运行此代码时,它会为我返回以下错误:

app.js:58464未捕获不变冲突:在“连接(提供程序)”的上下文或属性中找不到“存储”。或者将根组件包装在中,或者显式地将"store“作为属性传递给"Connect(Provider)”。

关于这段代码出了什么问题以及如何解决这个问题,你有什么想法吗?

EN

回答 1

Stack Overflow用户

发布于 2019-05-23 19:51:59

我也遇到了这个问题,并通过更新包解决了这个问题。你必须使用

  • react@^16.8.4
  • react-dom@^16.8.4
  • react-redux@^7.0.0
  • redux@^4.0.0
  • redux-thunk@^2.3.0

以下是对simplewebRTC的要求

https://docs.simplewebrtc.com/#/ReactVersions

票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/56083325

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