我需要创建手动json来将其作为输入发送到REST API。在过去的12c(v12.0.1.2)中,我使用Oracle,在做了一些研究后发现APEX_JSON 18c
我不能使用SQL/PL_SQL函数,因为我需要创建手动json。那么,有人能建议APEX_JSON在哪里更好吗?或者在性能和解析方面,拥有JSON_OBJECT_T、JSON_ARRAY_T、etc的新API更好?
这是我需要创建的样例JSON。在这个JSON中,只有routeStops数组可以从数据库中访问,并且将根据记录的数量有多个停靠点,但除此之外,其他值在整个json中都是单一的,并且需要硬编码值?因此,现在请建议我是否可以使用SQL函数来实现这一点?
"routeProfile": {
"resourceProfileRef": "7T5FRANBSC",
"driverRef": "",
"vehicleRef": "",
"dutyStartTime": "10:30",
"dutyDurationHours": 0,
"startLocation": {
"knownLocationRef": "",
"houseName": "",
"address1": "",
"address2": "",
"address3": "",
"address4": "",
"postCode": "",
"countryCode": "",
"location": {
"coordinates": [-999,
-999],
"type": "Point"
}
},
"mandatoryFirstStop": false,
"mandatoryFirstStopLocation": {
"knownLocationRef": "",
"houseName": "",
"address1": "",
"address2": "",
"address3": "",
"address4": "",
"postCode": "",
"countryCode": "",
"location": {
"coordinates": [-999,
-999],
"type": "Point"
}
},
"mandatoryFirstStopTime": 0,
"mandatoryLastStop": false,
"mandatoryLastStopLocation": {
"knownLocationRef": "",
"houseName": "",
"address1": "",
"address2": "",
"address3": "",
"address4": "",
"postCode": "",
"countryCode": "",
"location": {
"coordinates": [-999,
-999],
"type": "Point"
}
},
"mandatoryLastStopTime": 0,
"endLocation": {
"knownLocationRef": "",
"houseName": "",
"address1": "",
"address2": "",
"address3": "",
"address4": "",
"postCode": "",
"countryCode": "",
"countryCode": "",
"location": {
"coordinates": [-999,
-999],
"type": "Point"
}
}
},
"routeStops": [{
"stop": 1,
"location": {
"knownLocationRef": "",
"houseNumber": "",
"houseName": "Shop XYZ",
"address1": "Ruddington Lane",
"address2": "Wilford",
"address3": "Nottingham",
"address4": "",
"postCode": "NG11 7DQ",
"countryCode": "GB",
"location": {
"coordinates": [-999,
-999],
"type": "Point"
}
},
"jobs": [{
"jobRef": "3735081",
"jobTypeRef": "STDSTOPJOB",
"customer": {
"title": "",
"initials": "",
"firstName": "",
"lastName": "",
"homePhone": "",
"workPhone": "",
"mobilePhone": "",
"email": ""
},
"location": {
"knownLocationRef": "",
"houseNumber": "",
"houseName": "Shop XYZ",
"address1": "Ruddington Lane",
"address2": "Wilford",
"address3": "Nottingham",
"address4": "",
"postCode": "NG11 7DQ",
"countryCode": "GB",
"location": {
"coordinates": [-999,
-999],
"type": "Point"
}
},
"customerAccountRef": "CUSTACC001",
"jobScheduling": {
"schedulingDateTimeEarliest": "2018-12-21 00:00",
"schedulingDateTimeLatest": "2018-12-21 23:59",
"excludeDateTimeEarliest": "2018-12-21 12:00",
"excludeDateTimeLatest": "2018-12-21 13:00"
}
}]
}]发布于 2019-02-12 19:39:32
如果使用SQL select获取数据,则可以使用12.2中添加的JSON生成函数。它们是:
例如,下面的代码使用标准HR架构按部门创建一个employee对象数组:
select json_object (
'department' value d.department_name,
'employees' value json_arrayagg (
json_object (
'name' value first_name || ', ' || last_name,
'job' value job_title
))) DOC
from hr.departments d, hr.employees e, hr.jobs j
where d.department_id = e.department_id
and e.job_id = j.job_id
and d.department_id = 110
group by d.department_name;
DOC
{
"department" : "Accounting",
"employees" :
[
{
"name" : "Shelley, Higgins",
"job" : "Accounting Manager"
},
{
"name" : "William, Gietz",
"job" : "Public Accountant"
}
]
} 您可以在JSON Developer's Guide中找到有关这些内容的更多信息
https://stackoverflow.com/questions/54644055
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