未从json GET响应中删除"\n“的代码

Question

因此，我尝试从Json GET请求中删除一堆"\n“。但是，当我创建响应的字符串副本并尝试.replace("\n"，"")时，没有删除任何内容

def fetchProxy():
    return urllib.request.urlopen("https://api.getproxylist.com/proxy").read()


def createList():
    afile = open("proxies.json", "a")

    i = 1
    for i in range(3):
        proxy = str((fetchProxy())).replace("\n","",-1)
        afile.write(proxy + "\n")
    afile.close()

这是用于获取json并将其放入文件中的所有代码(超过3次)。此外，目前整个项目中几乎所有的代码。

示例json：

b'{\n    "_links": {\n        "_self": "\/proxy",\n        "_parent":
"\/"\n    },\n    "ip": "177.23.106.107",\n    "port": 4145,\n
"protocol": "socks4",\n    "anonymity": "high anonymity",\n
"lastTested": "2019-02-23 23:53:48",\n    "allowsRefererHeader":
true,\n    "allowsUserAgentHeader": true,\n    "allowsCustomHeaders":
true,\n    "allowsCookies": true,\n    "allowsPost": true,\n
"allowsHttps": true,\n    "country": "BR",\n    "connectTime":
"0.692",\n    "downloadSpeed": "155.000",\n    "secondsToFirstByte":
"1.128",\n    "uptime": "45.621"\n}'

Answer 1

这里有一个小技巧--基本上是一行。由于在JSON中通常忽略换行符和其他空格，因此您可以利用这一点，将response转换为Python字典，然后再将其转换回JSON。

import json
import urllib.request


def fetchProxy():
    response = urllib.request.urlopen("https://api.getproxylist.com/proxy").read()
    return json.dumps(json.loads(response))  # Clean up.

def createList():
    proxy = fetchProxy()  # Only do it once.

    with open("proxies.json", "a") as file:
        for _ in range(3):
            file.write(proxy + "\n")


if __name__ == '__main__':

    createList()

之后的proxies.json内容：

{"_links": {"_self": "/proxy", "_parent": "/"}, "ip": "177.66.42.126", "port": 4145, "protocol": "socks4", "anonymity": "high anonymity", "lastTested": "2019-02-27 12:43:02", "allowsRefererHeader": true, "allowsUserAgentHeader": true, "allowsCustomHeaders": true, "allowsCookies": true, "allowsPost": true, "allowsHttps": true, "country": "BR", "connectTime": "0.773", "downloadSpeed": "135.000", "secondsToFirstByte": "1.281", "uptime": "96.580"}
{"_links": {"_self": "/proxy", "_parent": "/"}, "ip": "177.66.42.126", "port": 4145, "protocol": "socks4", "anonymity": "high anonymity", "lastTested": "2019-02-27 12:43:02", "allowsRefererHeader": true, "allowsUserAgentHeader": true, "allowsCustomHeaders": true, "allowsCookies": true, "allowsPost": true, "allowsHttps": true, "country": "BR", "connectTime": "0.773", "downloadSpeed": "135.000", "secondsToFirstByte": "1.281", "uptime": "96.580"}
{"_links": {"_self": "/proxy", "_parent": "/"}, "ip": "177.66.42.126", "port": 4145, "protocol": "socks4", "anonymity": "high anonymity", "lastTested": "2019-02-27 12:43:02", "allowsRefererHeader": true, "allowsUserAgentHeader": true, "allowsCustomHeaders": true, "allowsCookies": true, "allowsPost": true, "allowsHttps": true, "country": "BR", "connectTime": "0.773", "downloadSpeed": "135.000", "secondsToFirstByte": "1.281", "uptime": "96.580"}

Answer 2

此调用：

    str((fetchProxy()))

将转义字符\n括起来。您想要调用替换为

    proxy = str((fetchProxy())).replace("\\n","")

或者，如果您希望将字符串值而不是字节保存在文件中：

    proxy = fetchProxy().decode().replace('\n', '')

Answer 3

您必须这样做，其中.replace("\n", "")是一个变量(我正在将您的第一个函数更改为一个变量，以便在第二个函数中可用，我希望这不会影响想要的结果)：

fetchProxy= return urllib.request.urlopen("https://api.getproxylist.com/proxy").read()
fetchProxy=str(fetchProxy)
fetchProxy=fetchProxy.replace("\n", "")


def createList():
    afile = open("proxies.json", "a")

    i = 1
    for i in range(3):
        proxy = fetchProxy 
#str((fetchProxy())).replace("\n","",-1) 
#I am not sure why the last argument in the .replace is -1, because the last argument is number of 
#occurences to be replaced and default is all, if left empty
        afile.write(proxy + "\n")
    afile.close()