以编程方式使用命令以设备所有者身份制作应用程序包

Question

作为设备所有者，我一直致力于制作软件包，但没有发现任何成功。我已经为我的设备建立了同样的根基。我正在使用这个命令。

                val exe = ShellExecuter()
                var command = "dpm set-device-owner $packageName/ .MyDeviceAdminReceiver"
                val outp = exe.Executer(command)

ShellExecuter代码段

public String Executer(String command) {
                    StringBuffer output = new StringBuffer();
                    Process p;
                    try {
                        p = Runtime.getRuntime().exec(command);
                        p.waitFor();
                        BufferedReader reader = new BufferedReader(new InputStreamReader(p.getInputStream()));
                        String line = "";
                        while ((line = reader.readLine())!= null) {
                            output.append(line + "\n");
                        }
                    } catch (Exception e) {`enter code here`
                        e.printStackTrace();
                    }
                    String response = output.toString();
                    return response;
                } 

MyDeviceAdminReceiver代码段

class MyDeviceAdminReceiver : DeviceAdminReceiver() {
    companion object {
        fun getComponentName(context: Context): ComponentName {
            return ComponentName(context.applicationContext, MyDeviceAdminReceiver::class.java)
        }

        private val TAG = MyDeviceAdminReceiver::class.java.simpleName
    }

    override fun onLockTaskModeEntering(context: Context?, intent: Intent?, pkg: String?) {
        super.onLockTaskModeEntering(context, intent, pkg)
        Log.d(TAG, "onLockTaskModeEntering")
    }

    override fun onLockTaskModeExiting(context: Context?, intent: Intent?) {
        super.onLockTaskModeExiting(context, intent)
        Log.d(TAG, "onLockTaskModeExiting")
    }
}

device_admin_reciever代码段

<?xml version="1.0" encoding="utf-8" standalone="yes" ?>
<device-admin>
    <uses-policies>
        <limit-password />
        <watch-login />
        <reset-password />
        <force-lock />
        <wipe-data />
        <expire-password />
        <encrypted-storage />
        <disable-camera />
    </uses-policies>
</device-admin>

我想让我的根植设备拥有我的应用程序包，使用命令或任何其他方式，如果有人可以建议的话。

Answer 1

如果您是设备上的root用户，则可以按照此方法成为设备所有者。

首先，创建一个包含以下内容的文件device_owner.xml：

<?xml version="1.0" encoding="utf-8" standalone="yes" ?>
<device-owner package="your.owner.app.package.id" name="Your app name" />

现在执行以下步骤

adb push device_owner.xml /sdcard/

adb shell

su

cp /sdcard/device_owner.xml /data/system/

cd /data/system/

chown system:system device_owner.xml

reboot

注意:在重新启动设备之前，请确保您已安装应用程序，您正尝试将其设置为设备所有者。如果您不这样做，您将获得无限时间的启动动画。

检查此问题How to make my app a device owner?

Answer 2

创建xml文件并从您的代码复制到正确的位置/data/system/device_owner.xml，然后执行此代码以设置适当的权限。并调用reboot命令

final String[] run_cmd = new String[]{"chown","system:system","/data/system/device_owner.xml"};
String reboot = "/system/bin/reboot";

execute(null,run_cmd);
execute(null,reboot);


 public void execute(Map<String, String> environvenmentVars, String[] cmd) {

            try {

                Process process = Runtime.getRuntime().exec(cmd);
                BufferedReader reader = new BufferedReader(new InputStreamReader(process.getInputStream()));

                StringBuffer output = new StringBuffer();

                char[] buffer = new char[4096];
                int read;

                while ((read = reader.read(buffer)) > 0) {
                    output.append(buffer, 0, read);
                }

                reader.close();

                process.waitFor();    
                BufferedReader reader2 = new BufferedReader(new InputStreamReader(process.getErrorStream()));    
                StringBuffer output2 = new StringBuffer();

                char[] buffer2 = new char[4096];
                int read2;

                while ((read2 = reader2.read(buffer2)) > 0) {
                    output2.append(buffer2, 0, read2);
                }

                reader.close();
                process.waitFor();
                }

            catch (Exception e)
            {

            }

        }