Google自定义设备操作在Raspberry Pi Google Assistant上出现错误

Question

我正在我的Raspberry Pi 3上创建一个google助手，并且我正在尝试创建一个自定义的设备操作，以最终打开我的车库门。它所做的一切就是在这个时间点上玩LED。

这是我的actions.json文件：

{
    "manifest": {
        "displayName": "Garage door",
        "invocationName": "Garage door",
        "category": "PRODUCTIVITY"
    },
    "actions": [
        {
            "name": "me.custom.actions.GarageDoor",
            "availability": {
                "deviceClasses": [
                    {
                        "assistantSdkDevice": {}
                    }
                ]
            },
            "intent": {
                "name": "me.custom.intents.GarageDoor",
                "trigger": {
                    "queryPatterns": [
                        "open the garage door",
                        "close the garage door"
                    ]
                }
            },
            "fulfillment": {
                "staticFulfillment": {
                    "templatedResponse": {
                        "items": [
                            {
                                "simpleResponse": {
                                    "textToSpeech": "Okay"
                                }
                            },
                            {
                                "deviceExecution": {
                                    "command": "me.custom.commands.GarageDoor"
                                }
                            }
                        ]
                    }
                }
            }
        }
    ],
    "types": []
}

但是当我运行这个命令时，我得到了这个错误：

INFO:root:Transcript of user request: "open the garage door".
INFO:root:Playing assistant response.
WARNING:root:Error during command execution
Traceback (most recent call last):
  File "/home/pi/assistant-sdk-python/google-assistant-sdk/googlesamples/assistant/grpc/device_helpers.py", line 94, in dispatch_command
    self.handlers[command](**params)
TypeError: gdoor() argument after ** must be a mapping, not NoneType

这是我的处理程序：

@device_handler.command('me.custom.commands.GarageDoor')
    def gdoor(*args):
        print(args)
        global g_open
        if g_open:
            GPIO.output(18, 0)
            g_open = 0
        else:
            GPIO.output(18, 1)
            g_open = 1

我尝试了一下*args，看看它是否修复了什么--它没有。为了保护隐私，我已经把我的包名改成了custom。我对此很困惑。感谢任何人的帮助！

谢谢!

Answer 1

看看the sample code，看起来函数签名有点不同，因为它直接添加了参数。

@device_handler.command('com.example.commands.BlinkLight')
def blink(speed, number):
    logging.info('Blinking device %s times.' % number)
    delay = 1
    if speed == "SLOWLY":
        delay = 2
    elif speed == "QUICKLY":
        delay = 0.5
    for i in range(int(number)):
        logging.info('Device is blinking.')
        time.sleep(delay)

查看操作包，您似乎没有提供任何操作来配合命令执行。如the sample所示

{
    "deviceExecution": {
        "command": "com.example.commands.BlinkLight",
        "params": {
            "speed": "$speed",
            "number": "$number"
        }
    }
}

如果没有任何参数，它可能根本不会映射任何函数。