我的PostgreSQL数据库中有以下模式:
CREATE TABLE survey_results (
id integer NOT NULL
);
CREATE TABLE slide_results (
id integer NOT NULL,
survey_result_id integer,
buttons jsonb DEFAULT '[]'::jsonb
);
INSERT INTO survey_results (id)
VALUES (1);
INSERT INTO slide_results (id, survey_result_id, buttons)
VALUES (1, 1, '[{"text": "Not at all"}, {"text": "Yes"}]');
INSERT INTO slide_results (id, survey_result_id, buttons)
VALUES (2, 1, '[{"text": "No"}, {"text": "Yes"}]');和以下查询:
WITH data AS (
select
sr.id ,
jsonb_agg(row_to_json(slr)) AS json_row
from slide_results slr
INNER JOIN survey_results sr ON sr.id = slr.survey_result_id
group by sr.id
)
SELECT id, json_row->0->>'buttons' from data;它返回:
| id | ?column? |
| --- | ----------------------------------------- |
| 1 | [{"text": "Not at all"}, {"text": "Yes"}] |我希望这个查询只返回按钮数组的第一个元素。我尝试了这样的东西:
WITH data AS (
select
sr.id ,
jsonb_agg(row_to_json(slr)) AS json_row
from slide_results slr
INNER JOIN survey_results sr ON sr.id = slr.survey_result_id
group by sr.id
)
SELECT id, json_row->0->>'buttons'->>1 from data;但这将返回错误:
Query Error: error: operator does not exist: text ->> integer我怎么才能修复它呢?
发布于 2018-12-05 02:44:43
SELECT id, json_row->0->'buttons'->>0 from data;您将'buttons'引用为文本,而不是对象。
另外,数组的索引是从0开始的,因此指向1将产生第二个元素。
https://stackoverflow.com/questions/53619282
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