无法从其他函数获取信息以查找高于和低于平均值的10个

Question

我正在尝试创建4个独立的函数，它们在输出文件中创建一个包含10000个函数的随机列表，然后找出从1到100范围内所有数字的平均值，然后找出有多少数字在平均值的10以上和10以下。这是我一直在做的事情的一个非常粗略的基础，但我不知道从哪里开始

def main():
    import random
    list=[]
    outfile = open("pa8_numbers.py","w") # open a file to WRITE to it
    for i in range(10000):
        data = random.randint(1,100)
        list.append(data)
        outfile.write(str(data)+"\n") # write the random number as a string
    outfile.close()


    print(above(list))



def numbers(data):
    list=[]
    for i in range(10000):
        data=random.randint(1,100)
        list.append(data)
    return list

def average(list):
    avg=sum(list)/len(list)
    return avg


def above(list):
    total=0
    average=sum(list)/len(list)
    averager=average+10
    for i in list:
        if average <=i and average >= i:
            total=total+i
            above.append(data[i])

            return above[i]
        else:
            break
def below(data):
    average=sum(list)/len(list)
    averager=average-10
    for i in range(len(list)):
        if average >= i and averager <= i:
            return below
        else:
            break
def final(self):
    print(above(list))
    print(average(list))
    print(below(list))






main()

Answer 1

我猜你需要下面的解决方案：

import random

aa = []
for i in range(10000):
    aa.append(random.randint(1,100))
avg = (sum(aa)/len(aa))
abv, blv = avg +10, avg-10

final_list = [1 if i>= abv else 2 if i<=blv else 0 for i in aa]

print ("numbers above, average+10 = ", abv , " --> ", final_list.count(1))
print ("numbers below, average-10 = ", blv , " --> ", final_list.count(2))
print ("numbers above, between(+10 and -10) = ''", blv, ":", abv , "' --> ", final_list.count(0))