使outoutcome中的结果包含申请编号或按发布编号查询申请编号

Question

SELECT 
  c.publication_number AS Pub, 
  COUNT(DISTINCT REGEXP_EXTRACT(p.publication_number, r'(.+-.+)-')) AS CitedByCount
FROM `patents-public-data.patents.publications` AS p, 
UNNEST(citation) AS c 
WHERE c.publication_number IN (
  SELECT publication_number 
  FROM `patents-public-data.patents.publications`
  WHERE application_number IN ('CN-201510747352-A') 
)
GROUP BY c.publication_number

我可以使用应用程序编号来获取CitedBy，但结果是Pub和CitedBy。如何实现结果包含申请号和CitedBy的目的？

Answer 1

也许你不想要group by

select c.publication_number as Pub, 
       regexp_extract(p.publication_number, r'(.+-.+)-')) as cited_by
from `patents-public-data.patents.publications` p cross join 
     unnest(citation) c 
where c.publication_number in (select publication_number 
                               from `patents-public-data.patents.publications`
                               where application_number in ('CN-201510747352-A') 
                              );

或者，您可以将它们聚合到一个数组中：

select c.publication_number as Pub, 
       array_agg(distinct regexp_extract(p.publication_number, r'(.+-.+)-'))) as cited_bys
from `patents-public-data.patents.publications` p cross join 
     unnest(citation) c 
where c.publication_number in (select publication_number 
                               from `patents-public-data.patents.publications`
                               where application_number in ('CN-201510747352-A') 
                              )
group by c.publication_number;