对发送到命令的c#命令使用引号

Question

我已经搜索了很多关于这方面的信息，但没有任何针对这种特定情况的示例。

我想压缩写在文本框(dirdes)上的目录，并在富文本框(_output)上显示输出。

它不是压缩写在文本框上的目录，而是压缩bin目录。

private void button3_Click(object sender, EventArgs e)
{
    string dirdes1 = dirdes.Text;
    string strCmdText;
    strCmdText = "/C compact /c /s /a /i /exe:lzx '" + dirdes1 + " *'";
    Process lzx = new Process();
    System.Diagnostics.Process process = new System.Diagnostics.Process();
    System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
    startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
    lzx.StartInfo.FileName = "cmd.exe";
    lzx.StartInfo.UseShellExecute = false;
    lzx.StartInfo.Arguments = strCmdText;
    lzx.StartInfo.RedirectStandardOutput = true;
    lzx.Start();
    _output.Text = lzx.StandardOutput.ReadToEnd();
}

编辑:我认为这是一个引用错误。因为目录必须像这样的"C:\"，而不像这样的'C:\'

Answer 1

我在GUI中混合了文本框名称...这花了我24小时！我稍微修改了一下代码。现在它开始工作了

private void button3_Click(object sender, EventArgs e)
    {
        string dirdes1 = dirdes.Text;
        string strCmdText;
        string locationAddress;
        string cdCommand;
        string doCompress;
        locationAddress = dirdes1;
        cdCommand  = "/C " + "cd " + locationAddress;
        strCmdText = "compact /c /s /a /i /exe:lzx";
        doCompress = "/C " + strCmdText + " *";
        Process lzx = new Process();
        System.Diagnostics.Process process = new System.Diagnostics.Process();
        System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
        startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
        lzx.StartInfo.FileName = "cmd.exe";
        lzx.StartInfo.UseShellExecute = false;
        lzx.StartInfo.WorkingDirectory = @locationAddress;
        lzx.StartInfo.Arguments = doCompress;
        lzx.StartInfo.RedirectStandardOutput = true;
        lzx.Start();
        _output.Text = lzx.StandardOutput.ReadToEnd();
        showCommand.Text = doCompress;

    }

有些变量是用来测试的，不用担心