我有一个问题,我有多个具有相同签名的方法(都返回void)。我希望能够组合这些方法的methodHandles,以获得依次调用每个方法的methodHandle。
我想要做到这一点的唯一方法是使用guardWithTest,我有一个如何在https://gist.github.com/gregw/b6c926fb44fd9a45b2c5afccaf7dcbf4上工作的示例:
但代码的本质是:‘java
TestMethodHandle test = new TestMethodHandle();
MethodHandle callA = MethodHandles.lookup().findVirtual(TestMethodHandle.class,"callA", methodType(Void.TYPE, String.class, Integer.TYPE)).bindTo(test);
MethodHandle callB = MethodHandles.lookup().findVirtual(TestMethodHandle.class,"callB", methodType(Void.TYPE, String.class, Integer.TYPE)).bindTo(test);
MethodHandle callC = MethodHandles.lookup().findVirtual(TestMethodHandle.class,"callC", methodType(Void.TYPE, String.class, Integer.TYPE)).bindTo(test);
MethodHandle asGuard = MethodHandles.lookup().findStatic(TestMethodHandle.class,"alwaysTrue", MethodType.methodType(Boolean.TYPE));
MethodHandle guardA = MethodHandles.filterReturnValue(callA,asGuard);
MethodHandle guardB = MethodHandles.filterReturnValue(callB,asGuard);
MethodHandle guardC = MethodHandles.filterReturnValue(callC,asGuard);
MethodHandle empty = empty(methodType(Void.TYPE, String.class, Integer.TYPE));
MethodHandle invokeC = MethodHandles.guardWithTest(guardC,empty,empty);
MethodHandle invokeBC = MethodHandles.guardWithTest(guardB,invokeC,empty);
MethodHandle invokeABC = MethodHandles.guardWithTest(guardA,invokeBC,empty);
invokeABC.invoke("chained", 2);有没有更简单的方法来做这件事?
补充问题...我应该这样做吗?还是在一组方法句柄上调用methodHandles in循环会同样快?
发布于 2018-10-24 15:56:57
我认为这样可能会更好:
MethodHandle callA = MethodHandles.lookup().findVirtual(TestMethodHandle.class,"callA", methodType(Void.TYPE, String.class, Integer.TYPE)).bindTo(test);
MethodHandle callB = MethodHandles.lookup().findVirtual(TestMethodHandle.class,"callB", methodType(Void.TYPE, String.class, Integer.TYPE)).bindTo(test);
MethodHandle callC = MethodHandles.lookup().findVirtual(TestMethodHandle.class,"callC", methodType(Void.TYPE, String.class, Integer.TYPE)).bindTo(test);
MethodHandle foldedABC = MethodHandles.foldArguments(MethodHandles.foldArguments(callC,callB),callA);
foldedABC.invoke("folded", 42);https://stackoverflow.com/questions/52962364
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