如何检查状态码200或不使用swift？

Question

我正在尝试验证我的响应状态代码是否等于200，但==或!=不工作。请给我一些样品。

JSON Response:{
    message = "registered Successfull";
    result =     {
        "created_by" = "2012-03-14 07:26:31";
        "created_ts" = "2013-03-14 07:26:31";
        "c_email" = "jk@mail.com";
        "c_lastname" = hi;
        "c_name" = sc;
        id = 123;
        login =         {
            authorization = z2VIownsD0Pr1jIMhJE;
        };
        "phone_no" = 123XXXX;
    };
    status = 1;
    "status_code" = 200;
}

下面是我的代码

let status_code = result["status_code"]  as? [String: AnyObject]           
if (status_code! == "200") {
    print("ERROR:\(String(describing: status_code))")
} else {
    let results = result["result"]  as? [String: AnyObject]
    if let login = results!["login"]  as? [String: AnyObject] {
        let authorization = login["authorization"] as? String
        print(authorization ?? "")
    }
    self.navigatepop() // Not working
}

Answer 1

如果status_code在String中，您可以尝试

if let json = response.result.value as? [String: Any] {
  let status_code : String = json["status_code"]! as! String 
    // here you can check if it is in Integer format
    if(status_code == "200") {
      //Your code after success code
      }
}

Answer 2

 if let json = response.result.value{
    let responseDict = json as! NSDictionary
    if let statusCode = responseDict.object(forKey: "status_code") as? Int {
        print(statusCode)
    }
}

Answer 3

在json中："status_code" = 200; status_code是Int值，因此必须取消交换

let status_code = result["status_code"]  as?  Int{   // not as? [String: AnyObject]  or can : as? String

if (status_code! == "200") {为status_code == 200或status_code == "200"