以下是我正在使用的queryie的简化版本:
SELECT
r.id,
r.nr,
MAX(CASE WHEN (rm.meta_key = 'supplier_id') THEN (SELECT suppliers.title FROM suppliers WHERE suppliers.id = rm.meta_value) ELSE NULL END) AS supplier,
MAX(CASE WHEN (rm.meta_key = 'client_id') THEN (SELECT clients.name FROM clients WHERE clients.id = rm.meta_value) ELSE NULL END) AS client,
FROM `registries` AS r
INNER JOIN `registries_meta` AS rm ON `r`.`id` = `rm`.`registries_id`
GROUP BY r.id
LIMIT 100这里有可能避免子查询吗?我需要告诉Mysql "Join registries_metas,如果meta_key是client_id,JOIN clients.id = meta_value并选择clients.name“。
谢谢。
发布于 2018-09-30 19:35:40
我相信您想要的逻辑只使用join
SELECT r.id, r.nr,
c.name as client_name, s.title as supplier
FROM registries r INNER JOIN
registries_meta rm
ON r.id = rm.registries_id LEFT JOIN
clients c
ON rm.meta_value = c.id AND rm.meta_key = 'client_id' LEFT JOIN
suppliers s
ON rm.meta_value = s.id AND rm.meta_key = 'supplier_id';如果您可以有多个客户/供应商,您可能希望所有客户/供应商都在一行中。这意味着聚合:
SELECT r.id, r.nr,
GROUP_CONCAT(c.name) as client_names,
GROUP_CONCAT(s.title) as suppliers
FROM registries r INNER JOIN
registries_meta rm
ON r.id = rm.registries_id LEFT JOIN
clients c
ON rm.meta_value = c.id AND rm.meta_key = 'client_id' LEFT JOIN
suppliers s
ON rm.meta_value = s.id AND rm.meta_key = 'supplier_id'
GROUP BY r.id, r.nr;发布于 2018-09-30 19:07:28
与客户和供应商表进行左连接
SELECT
r.id,
r.nr,
c.name AS client_name,s.title as supplier
FROM `registries` AS r
INNER JOIN `registries_meta` AS rm ON `r`.`id` = `rm`.`registries_id`
left join clients c on rm.meta_value=c.id
left join suppliers s on rm.meta_value=suppliers.id发布于 2018-09-30 19:14:36
尝试向左连接到clients表。我的直觉告诉我,我们需要对子查询进行透视,以便为每个键找到正确的元值。然后,我们可以使用该元值(应该是客户端ID)左连接到clients。
SELECT
t.id,
t.nr,
t.client AS client_id,
COALESCE(c.name, '') AS client_name,
t.supplier AS supplier_id,
COALESCE(s.title, '') AS supplier_title
FROM
(
SELECT
r.id,
r.nr,
MAX(CASE WHEN rm.meta_key = 'client_id' THEN rm.meta_value END) AS client,
MAX(CASE WHEN rm.meta_key = 'supplier_id' THEN rm.meta_value END) AS supplier
FROM registries AS r
INNER JOIN registries_meta AS rm
ON r.id = rm.registries_id
GROUP BY r.id
) t
LEFT JOIN clients AS c
ON t.client = c.id
LEFT JOIN suppliers AS s
ON t.supplier = s.id;https://stackoverflow.com/questions/52577277
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