我想在y=0上找到一个函数的x值。
from pynverse import inversefunc
from math import pi,sqrt
R=20
C=5*10**-9
L=5*10**-4
Z= (lambda x: sqrt(R**2+(1/(2*pi*C*x)-2*pi*L*x)**2))
inversefunc(Z,y_values=0)但我得到了以下错误代码:
Traceback (most recent call last):
File "<pyshell#16>", line 1, in <module>
inversefunc(Z,y_values=0)
File "C:\Python27\lib\site-packages\pynverse\inverse.py", line 113, in inversefunc
trend = np.sign(func(ref2, *args) - func(ref1, *args))
File "<pyshell#15>", line 1, in <lambda>
Z= (lambda x: sqrt(R**2+(1/(2*pi*C*x)-2*pi*L*x)**2))
ZeroDivisionError: float division by zero请告诉我为什么!谢谢。
发布于 2018-10-05 22:23:01
当除数为0时,您可以告知答案是未定义的,并且您应该使用普通函数,而不是python中命名为lambdas的函数。
from pynverse import inversefunc
from math import pi,sqrt
def Z(x):
# Can define these globally if necessary.
R = 20
C = 5 * 10**-9
L = 5 * 10**-4
return sqrt(R**2 + (1/(2*pi*C*x) - 2*pi*L*x)**2))
try:
inversefunc(Z, y_values=0)
except ZeroDivisionError:
print("answer is undefined")https://stackoverflow.com/questions/52667343
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