我在app.config包中创建了一个RouteConfig类,如下所示:
public class RouteConfig extends AbstractRouteConfig {
@Override
public void init(AppContext appContext) {
route("/{controller}/{aut_id}/").to(AuthorsController.class).action("findById");
}我创建了AppControllerConfig类:
package app.config;
import app.controllers.CatchAllFilter;
import app.controllers.api.v2.AuthorsController;
import org.javalite.activeweb.AbstractControllerConfig;
import org.javalite.activeweb.AppContext;
import org.javalite.activeweb.controller_filters.DBConnectionFilter;
public class AppControllerConfig extends AbstractControllerConfig {
public void init(AppContext context) {
add(new DBConnectionFilter(), new CatchAllFilter()).to(AuthorsController.class);
}
}我还定义了如下的APIController类:
package app.controllers;
import org.javalite.activeweb.AppController;
public abstract class APIController extends AppController {
@Override
protected String getContentType() {
return "application/json";
}
@Override
protected String getLayout() {
return null;
}
}AuthorsController在app.controllers.api.v2包中:
import app.controllers.APIController;
import app.models.Author;
public class AuthorsController extends APIController {
public void findById() {
if (blank("aut_id")) {
throw new RuntimeException("aut_id number is mandatory but was empty or null");
} else {
Author author = Author.findById(param("aut_id"));
String jsonResponse = author.toJson(false);
respond(jsonResponse);
}
}
}当尝试访问url http://localhost:8080/api/v2/authors/9时,我收到以下错误:
Request properties: Request URL: http://localhost:8080/api/v2/authors/9
ContextPath:
Query String: null
URI Full Path: /api/v2/authors/9
URI Path: /api/v2/authors/9
Method: GET
Request parameters: {}
Request headers: {Cookie=_ga=GA1.1.1833610632.1527846931; JSESSIONID=node03k88mhw4nihozrzi9ehiiadj0.node0, Cache-Control=no-cache, Accept=text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8, Upgrade-Insecure-Requests=1, Connection=keep-alive, User-Agent=Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/68.0.3440.106 Safari/537.36, Host=localhost:8080, Pragma=no-cache, Accept-Encoding=gzip, deflate, br, Accept-Language=en,fr;q=0.9,ru;q=0.8}
org.javalite.activeweb.ActionNotFoundException: java.lang.NoSuchMethodException: app.controllers.api.v2.AuthorsController.9(); app.controllers.api.v2.AuthorsController.9()
[qtp1987707214-16] WARN ParamCopy - found 'session' value set by controller. It is reserved by ActiveWeb and will be overwritten.
[qtp1987707214-16] INFO FreeMarkerTemplateManager - rendering template: '/system/404' with layout: '/layouts/default_layout', session: node018slc2f7n5p0v67173ezr8guc0
[qtp1987707214-16] WARN FreeMarkerTemplateManager - Current location: /Users/Serguei/projects/java/newton-interventions
[qtp1987707214-16] ERROR RequestDispatcher - ActiveWeb internal error:
org.javalite.activeweb.ViewMissingException: Failed to render template: '/system/404.ftl', with layout: '/layouts/default_layout'; Template "/system/404.ftl" not found.我做错了什么?我甚至没有进入AuthorsController..。它似乎忽略了我的路由定义,并尝试查找以下路由定义:
"method":"GET","action":"9","error":"java.lang.NoSuchMethodException: app.controllers.api.v2.AuthorsController.9()在同一控制器中声明index操作时,如下所示:
public void index() {
final String json = Author.findFirst("AUT_ID = 9").toJson(false);
respond(json);
}点击http://localhost:8080/api/v2/authors,它就起作用了。
发布于 2018-09-18 05:06:10
这刷新了路由系统中的错误:https://github.com/javalite/activeweb/issues/397修复了错误,并将新快照部署到Sonatype版本: 2.3-SNAPSHOT。https://oss.sonatype.org/content/repositories/snapshots/org/javalite/activeweb/2.3-SNAPSHOT/
现在,您可以尝试查看此方法是否有效。BWT,感谢你的详细描述,它帮助设置了正确的规范:RouterCustomSpec
发布于 2018-09-17 23:12:45
最后,我想出了如何让它工作。
我更改了RouteConfig类中的路由声明,如下所示:
route("/{controller}/find-by-id}/{id}").to(AuthorsController.class).action("findById");我在AuthorsController中更改了findById方法,如下所示:
public void findById() {
System.out.println(params());
if (blank("id")) {
throw new RuntimeException("autId number is mandatory but was empty or null");
} else {
Author author = Author.findById(param("id"));
String jsonResponse = author.toJson(false);
respond(jsonResponse);
}
}似乎按照惯例,作为数字传递给url的参数名称被认为是id,而不是其他,对吧?
https://stackoverflow.com/questions/52369883
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