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社区首页 >问答首页 >gsub不会替换列中的名称

gsub不会替换列中的名称
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Stack Overflow用户
提问于 2018-08-05 18:22:07
回答 1查看 60关注 0票数 1

使用R时,具有列Certificate...HQA的my data frame capstone3具有以下级别:

代码语言:javascript
复制
levels(capstone3$Certificate...HQA)

 [1] "CUM LAUDE"                     "DIPLOM"                       
 [3] "DOCTORATE"                     "GRADUATE DIPLOMA"             
 [5] "HIGHEST HONS"                  "HONOURS (DISTINCTION)"        
 [7] "HONOURS (HIGHEST DISTINCTION)" "HONS"                         
 [9] "HONS I"                        "HONS II"                      
[11] "HONS II LOWER"                 "HONS II UPPER"                
[13] "HONS III"                      "HONS UNCLASSIFIED"            
[15] "HONS WITH MERIT"               "MAGNA CUM LAUDE"              
[17] "MASTER'S DEGREE"               "OTHER HONS"                   
[19] "PASS DEGREE"                   "PASS WITH CREDIT"             
[21] "PASS WITH DISTINCTION"         "PASS WITH HIGH MERIT"         
[23] "PASS WITH MERIT"               "SUMMA CUM LAUDE" 

我写了一个代码来减少级别的数量,用级别9替换级别7,用级别12替换级别6,依此类推:

代码语言:javascript
复制
capstone3$Certificate...HQA <- as.factor(capstone3$Certificate...HQA)

capstone3$Certificate...HQA <- gsub("HONOURS (HIGHEST DISTINCTION)","HONS I", capstone3$Certificate...HQA)

capstone3$Certificate...HQA <- gsub("HONOURS (DISTINCTION)","HONS II UPPER", capstone3$Certificate...HQA)

capstone3$Certificate...HQA <- gsub("HONS WITH MERIT","HONS II LOWER", capstone3$Certificate...HQA)

但是上面的gsub代码并没有替换列中的名字,有人能指出我代码的问题吗?

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回答 1

Stack Overflow用户

发布于 2018-08-05 18:23:55

圆括号()是正则表达式中用于创建组的特殊字符。如果有文字圆括号,则需要使用\\对它们进行转义

代码语言:javascript
复制
gsub("HONOURS \\(HIGHEST DISTINCTION\\)","HONS I", capstone3$Certificate...HQA)

或者像@ManuelBickel一样:使用fixed = TRUE,模式是一个字符串,将按原样匹配。

代码语言:javascript
复制
gsub("HONOURS (HIGHEST DISTINCTION)","HONS I", capstone3$Certificate...HQA, fixed = TRUE)
票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/51693437

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