我正在尝试寻找一个图(邻接矩阵)中的最大团,这个图可以有50个节点。目前,当图的大小达到n=40左右时,我所拥有的开始永远耗费时间。有没有人能找到我能做的优化?
public static void maxClique(Graph graph, List<Integer> clique) {
//Get the newest node added to the clique
int currentValue = clique.get(clique.size() - 1);
if (clique.size() > max.size()) {
max = clique;
}
// Check every node
for (int i = 0; i < graph.size; i++) {
// If the node being checked is connected to the current node, and isn't the current node
if (graph.matrix[currentValue][i] == 1 && !clique.contains(i)) {
//Check if the new clique is bigger than the current max.
//Make a new clique and add all the nodes from the current clique to it
ArrayList<Integer> newClique = new ArrayList<>();
newClique.addAll(clique);
//Add the new node
newClique.add(i);
//Repeat
if (makesNewClique(graph, clique, i)) {
maxClique(graph, newClique);
}
}
}
}全班内容:https://pastebin.com/fNPjvgUm邻接矩阵:https://pastebin.com/yypN9K4L
发布于 2020-10-04 13:00:21
David Eisenstat的评论给出了答案,这是我为稍后来到这里的任何人提供的代码:
public void bronKerbosh(Set<Integer> p, Set<Integer> r, Set<Integer> x) {
if (x.isEmpty() && p.isEmpty() && r.size() > max.size()) {
max = new ArrayList<>();
max.addAll(r);
}
Object[] pArr = p.toArray();
for (Object vTemp : pArr) {
int v = (int)vTemp;
Set<Integer> newR = new HashSet<>();
newR.addAll(r);
newR.add(v);
bronKerbosh(intersect(p, neighbors(v)), newR, intersect(x, neighbors(v)));
p.remove(v);
x.add(v);
}
}https://stackoverflow.com/questions/64190700
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