在嵌套的For-Loop中查找元素

Question

我的代码中有两个名为extra和be的列表。

extra输出为[7,27]和

be输出为

'Feed Forage', '', '', '', 'Social Play', '', 'Feed Forage', 'Nonsocial Play', '', 'Nonsocial Play', '', '', '', '', 'Nonsocial Play', '', '', '', '', '', '', '', '', 'Social Play', '', '', '', '', '', '', '', '', 'Nonsocial Play', 'Groom', 'Feed Forage', '', '', 'Nonsocial Play', '', '', 'Feed Forage', '', 'Feed Forage', '', 'Feed Forage', '', 'Social Play', '', 'Social Play', '', '', 'Social Play', '', '', '', '', '', 'Feed Forage', '', '', '', '', 'Feed Forage', '', '', '', '', 'Feed Forage', '', '', 'Feed Forage', '', '', '', '', '', 'Feed Forage', '', '', '', 'Groom', 'Groom', '', '', '', '', 'Groom', 'Groom', 'Groom', '', 'Groom', '', '', '', 'Feed Forage', '', '', 'Feed Forage', 'Nonsocial Play', '', '', '', 'Pace', '', '', '', 'Feed Forage', '', 'Nonsocial Play', '', 'Feed Forage', '', 'Social Play', '', 'Feed Forage', '', 'Social Play', '', 'Social Play', '', '', '', '', '', 'Nonsocial Play', '', 'Social Play', '', '', '', '', 'Feed Forage', '', '', '', '', '', '', '', 'Nonsocial Play', '', 'Nonsocial Play', '', 'Feed Forage', 'Social Play', '', '', '', 'Feed Forage', '', 'Nonsocial Play', '', '', 'Feed Forage', '', '', '', '', 'Self Groom', '', '', 'Groom', '', '', 'Self Groom', '', '', '', '', '', 'Groom', '', '', 'Self Groom', '', '', 'Feed Forage', '', '', '', '', '', 'Pace', '', 'Self Groom', '', '', '', 'Self Groom', '', 'Self Groom', '', 'Social Play', '', 'Social Play', '', 'Self Groom', 'Groom', '', '', 'Groom', '', 'Groom', '', 'Groom', 'Groom', 'Groom', '', '', 'Self Groom', '', 'Groom', '', 'Groom', '', 'Feed Forage', '', 'Feed Forage', '', 'Feed Forage', '', '', '', '', '', '', '', 'Feed Forage', '', '', '', '', 'Feed Forage', 'Nonsocial Play', '', '', 'Self Groom', 'Nonsocial Play', '', '', '', 'Groom', '', '', 'Groom', '', 'Groom', '', '', 'Groom', '', '', 'Groom', '', '', 'Groom', '', '', '', '', '', '', 'Groom', 'Groom', '', 'Groom', '', '', 'Groom', '', '', '', 'Self Groom', '', '', '', '', '', '', 'Groom', '', 'Groom', '', 'Feed Forage', '']

我需要找到extra的第7和27个单词元素(即，如果元素是空字符串，则不算数)。它应该是Nonsocial Play和Groom，但是我的for循环只打印Nonsocial Play

下面是我正在使用的for循环：

for x in extra:
count = 0
for y in be:
    if y != '':
        if x == count:
            print(be[x])
            count += 1
        elif x != count:
            count += 1

如果你知道为什么它不工作，请让我知道！编辑:我想打印这些语句，但也需要删除它们

Answer 1

我创建了一个简单的函数filter_iter(itr)，用于过滤参数itr中的迭代值中的空值。然后，您可以使用list extra中的值访问过滤后的结果列表

extra = [7,27]
be = ['Feed Forage', '', '', '', 'Social Play', '', 'Feed Forage', 'Nonsocial Play', '', 'Nonsocial Play', '', '', '', '', 'Nonsocial Play', '', '', '', '', '', '', '', '', 'Social Play', '', '', '', '', '', '', '', '', 'Nonsocial Play', 'Groom', 'Feed Forage', '', '', 'Nonsocial Play', '', '', 'Feed Forage', '', 'Feed Forage', '', 'Feed Forage', '', 'Social Play', '', 'Social Play', '', '', 'Social Play', '', '', '', '', '', 'Feed Forage', '', '', '', '', 'Feed Forage', '', '', '', '', 'Feed Forage', '', '', 'Feed Forage', '', '', '', '', '', 'Feed Forage', '', '', '', 'Groom', 'Groom', '', '', '', '', 'Groom', 'Groom', 'Groom', '', 'Groom', '', '', '', 'Feed Forage', '', '', 'Feed Forage', 'Nonsocial Play', '', '', '', 'Pace', '', '', '', 'Feed Forage', '', 'Nonsocial Play', '', 'Feed Forage', '', 'Social Play', '', 'Feed Forage', '', 'Social Play', '', 'Social Play', '', '', '', '', '', 'Nonsocial Play', '', 'Social Play', '', '', '', '', 'Feed Forage', '', '', '', '', '', '', '', 'Nonsocial Play', '', 'Nonsocial Play', '', 'Feed Forage', 'Social Play', '', '', '', 'Feed Forage', '', 'Nonsocial Play', '', '', 'Feed Forage', '', '', '', '', 'Self Groom', '', '', 'Groom', '', '', 'Self Groom', '', '', '', '', '', 'Groom', '', '', 'Self Groom', '', '', 'Feed Forage', '', '', '', '', '', 'Pace', '', 'Self Groom', '', '', '', 'Self Groom', '', 'Self Groom', '', 'Social Play', '', 'Social Play', '', 'Self Groom', 'Groom', '', '', 'Groom', '', 'Groom', '', 'Groom', 'Groom', 'Groom', '', '', 'Self Groom', '', 'Groom', '', 'Groom', '', 'Feed Forage', '', 'Feed Forage', '', 'Feed Forage', '', '', '', '', '', '', '', 'Feed Forage', '', '', '', '', 'Feed Forage', 'Nonsocial Play', '', '', 'Self Groom', 'Nonsocial Play', '', '', '', 'Groom', '', '', 'Groom', '', 'Groom', '', '', 'Groom', '', '', 'Groom', '', '', 'Groom', '', '', '', '', '', '', 'Groom', 'Groom', '', 'Groom', '', '', 'Groom', '', '', '', 'Self Groom', '', '', '', '', '', '', 'Groom', '', 'Groom', '', 'Feed Forage', '']

def filter_iter(itr):
    return [i for i in itr if i]

be = filter_iter(be)
print([be[e] for e in extra])

打印：

['Nonsocial Play', 'Groom']

Answer 2

你也可以这样做

extra = [7,27]
be = ['Feed Forage', '', '', '', 'Social Play', '', 'Feed Forage', 'Nonsocial Play', '', 'Nonsocial Play', '', '', '', '', 'Nonsocial Play', '', '', '', '', '', '', '', '', 'Social Play', '', '', '', '', '', '', '', '', 'Nonsocial Play', 'Groom', 'Feed Forage', '', '', 'Nonsocial Play', '', '', 'Feed Forage', '', 'Feed Forage', '', 'Feed Forage', '', 'Social Play', '', 'Social Play', '', '', 'Social Play', '', '', '', '', '', 'Feed Forage', '', '', '', '', 'Feed Forage', '', '', '', '', 'Feed Forage', '', '', 'Feed Forage', '', '', '', '', '', 'Feed Forage', '', '', '', 'Groom', 'Groom', '', '', '', '', 'Groom', 'Groom', 'Groom', '', 'Groom', '', '', '', 'Feed Forage', '', '', 'Feed Forage', 'Nonsocial Play', '', '', '', 'Pace', '', '', '', 'Feed Forage', '', 'Nonsocial Play', '', 'Feed Forage', '', 'Social Play', '', 'Feed Forage', '', 'Social Play', '', 'Social Play', '', '', '', '', '', 'Nonsocial Play', '', 'Social Play', '', '', '', '', 'Feed Forage', '', '', '', '', '', '', '', 'Nonsocial Play', '', 'Nonsocial Play', '', 'Feed Forage', 'Social Play', '', '', '', 'Feed Forage', '', 'Nonsocial Play', '', '', 'Feed Forage', '', '', '', '', 'Self Groom', '', '', 'Groom', '', '', 'Self Groom', '', '', '', '', '', 'Groom', '', '', 'Self Groom', '', '', 'Feed Forage', '', '', '', '', '', 'Pace', '', 'Self Groom', '', '', '', 'Self Groom', '', 'Self Groom', '', 'Social Play', '', 'Social Play', '', 'Self Groom', 'Groom', '', '', 'Groom', '', 'Groom', '', 'Groom', 'Groom', 'Groom', '', '', 'Self Groom', '', 'Groom', '', 'Groom', '', 'Feed Forage', '', 'Feed Forage', '', 'Feed Forage', '', '', '', '', '', '', '', 'Feed Forage', '', '', '', '', 'Feed Forage', 'Nonsocial Play', '', '', 'Self Groom', 'Nonsocial Play', '', '', '', 'Groom', '', '', 'Groom', '', 'Groom', '', '', 'Groom', '', '', 'Groom', '', '', 'Groom', '', '', '', '', '', '', 'Groom', 'Groom', '', 'Groom', '', '', 'Groom', '', '', '', 'Self Groom', '', '', '', '', '', '', 'Groom', '', 'Groom', '', 'Feed Forage', '']

>>> [x for i, x in enumerate(s for s in be if s) if i in extra]
['Nonsocial Play', 'Groom']

Answer 3

Python 2

new_be=filter(lambda a: a != '', be) #we delete from the list all the '' and we save the new list in new_be
world=[]
for i in extra:
    world.append(new_be[int(i)])

print (world)

Python 3

    new_be=list(filter(("").__ne__, be)) #we delete from the list all the '' and we save the new list in new_be
    world=[]
    for i in extra:
        world.append(new_be[int(i)])

    print (world)

《非社交游戏》，《新郎》