spring JPA Hibernate MariaDB

Question

我正在尝试从我的spring JPA hibernate应用程序连接到mariaDB v10.2.14。我正在使用

driverClassName: com.mysql.jdbc.Driver

和

setProperty("hibernate.dialect", "org.hibernate.dialect.MySQL5Dialect");

我有一个查询方法，通过使用"findTop1“关键字来查找顶部第一行...当查询实际形成时，它使用“偏移量0行仅获取下一行1行”而不是限制0,1 ...因此，maria DB服务器抛出一个错误...

如何更改驱动程序/方言文件以使用LIMIT子句而不是offset-fetch形成查询。

注意:我已经尝试了mariadb方言和mariadb驱动程序类名的所有组合，如org.hibernate.dialect.MariaDB53Dialect和org.mariadb.jdbc.Driver。

下面是我得到的异常

2018-06-27 11:31:19.936  INFO 10484 --- [nio-8080-exec-2] o.h.h.i.QueryTranslatorFactoryInitiator  : HHH000397: Using ASTQueryTranslatorFactory
Hibernate: select aboutpage0_.id as id1_0_, aboutpage0_.APPLICATION_NAME as APPLICAT2_0_, aboutpage0_.createdDate as createdD3_0_, aboutpage0_.effectiveDate as effectiv4_0_, aboutpage0_.LAST_UPD_TS as LAST_UPD5_0_, aboutpage0_.LAST_UPD_SYSUSR_ID as LAST_UPD6_0_, aboutpage0_.version as version7_0_ from XXXXX aboutpage0_ where aboutpage0_.APPLICATION_NAME=? and aboutpage0_.effectiveDate<=? order by aboutpage0_.LAST_UPD_TS desc, aboutpage0_.effectiveDate desc offset 0 rows fetch next ? rows only
2018-06-27 11:31:20.112  WARN 10484 --- [nio-8080-exec-2] o.h.engine.jdbc.spi.SqlExceptionHelper   : SQL Error: 1064, SQLState: 42000
2018-06-27 11:31:20.112 ERROR 10484 --- [nio-8080-exec-2] o.h.engine.jdbc.spi.SqlExceptionHelper   : You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'offset 0 rows fetch next 1 rows only' at line 1
2018-06-27 11:31:20.142 ERROR 10484 --- [nio-8080-exec-2] o.a.c.c.C.[.[.[/].[dispatcherServlet]    : Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.dao.InvalidDataAccessResourceUsageException: could not extract ResultSet; SQL [n/a]; nested exception is org.hibernate.exception.SQLGrammarException: could not extract ResultSet] with root cause

com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'offset 0 rows fetch next 1 rows only' at line 1

Answer 1

预打印查询：

select  aboutpage0_.id as id1_0_, aboutpage0_.APPLICATION_NAME as APPLICAT2_0_,
        aboutpage0_.createdDate as createdD3_0_, aboutpage0_.effectiveDate as effectiv4_0_,
        aboutpage0_.LAST_UPD_TS as LAST_UPD5_0_, aboutpage0_.LAST_UPD_SYSUSR_ID as LAST_UPD6_0_,
        aboutpage0_.version as version7_0_
    from  XXXXX aboutpage0_
    where  aboutpage0_.APPLICATION_NAME=?
      and  aboutpage0_.effectiveDate<=?
    order by  aboutpage0_.LAST_UPD_TS desc,
              aboutpage0_.effectiveDate desc
    offset 0 rows fetch next ? rows only 2018-06-27 

这应该说明在从Hibernate创建SQL时出现了错误。它可能会指向limit 1 offset 0，但失败了。(注意：LIMIT先于OFFSET。)