在Python shell中使用“quotations而不是‘

Question

我正试着用python打印一个带有“引号”而不是“引号”的列表。

例如，我要给myList = ['a','b','c','d']什么我想要给myList = ["a","b","c","d"]什么

提前感谢！

Answer 1

您可以使用json来完成此操作

import json

myList = ['a','b','c','d']

out = json.dumps(myList)
print(out)
# ["a", "b", "c", "d"]

Answer 2

要做到这一点，最简单的方法是使用json (因为这恰好是JSON使用的格式)：

import json
print(json.dumps(['a', 'b', 'c', 'd'])

下面是关于如何在纯python中实现该功能的一些见解：

list类的内置__repr__方法只是在每个元素上调用__repr__ ...在本例中为str。

str.__repr__具有使用单引号的行为。没有(直接的)方法来改变这一点。

你可以使用它自己的__repr__函数来滚动你自己的类型，这样做就足够容易了……

class mystr(str):
  def __repr__(self):
     return '"' + str.__repr__(self)[1:-1].replace('"', r'\"') + '"'


yourlist = ['a', 'b', 'c', 'd']

# convert your list in place
for i,v in enumerate(yourlist):
  yourlist[i] = mystr(v)

print(yourlist)

Answer 3

您可以创建自己的字符串子类，其表示形式使用"字符：

class MyStr(str):
    # Special string subclass to override the default representation
    # method. Main purpose is to prefer using double quotes and avoid hex
    # representation on chars with an ord() > 128
    def __repr__(self):
        quotechar = '"'
        rep = [quotechar]
        for ch in self:
            # Control char?
            if ord(ch) < ord(' '):
                # remove the single quotes around the escaped representation
                rep += repr(str(ch)).strip("'")
            # Does embedded quote match quotechar being used?
            elif ch == quotechar:
                rep += "\\"
                rep += ch
            # Else just use others as they are.
            else:
                rep += ch
        rep += quotechar
        return "".join(rep)


myList = ['a','b','c','d']
print(myList)  # -> ['a', 'b', 'c', 'd']
print([MyStr(element) for element in myList])  # -> ["a", "b", "c", "d"]