请记住,我今天刚开始使用Python,所以我很糟糕。
您好,我正在编写一个机器人的不一致,我遇到了一个问题,当我运行它。我正在尝试将它放到网上,但我一直收到相同的错误。我不知道错误是从哪里来的。有人能帮帮忙吗?
到目前为止,我的代码如下:
import discord
from discord.ext.commands import bot
from discord.ext import commands
import asyncio
import time
Client = discord.Client()
client = commands.Bot(command_prefix = "~")
@client.event
async def on_ready():
print("I'm up on some BOOF!" + client.user.id)
print("I am the" + client.user.name)
@client.event
async def on_message(message):
if message.content == "Boof":
await client.send_message(message.channel, ":b:")
client.run("<redacted>")我得到的错误是:
Ignoring exception in on_ready
Traceback (most recent call last):
File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages/discord/client.py", line 307, in _run_event
yield from getattr(self, event)(*args, **kwargs)
File "/Users/johnathanhelsel/Documents/Boof Bot/BoofBot.py", line 13, in on_ready
print("I am the" + client.user.name)
File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/idlelib/run.py", line 362, in write
return self.shell.write(s, self.tags)
File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/idlelib/rpc.py", line 604, in __call__
value = self.sockio.remotecall(self.oid, self.name, args, kwargs)
File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/idlelib/rpc.py", line 216, in remotecall
return self.asyncreturn(seq)
File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/idlelib/rpc.py", line 247, in asyncreturn
return self.decoderesponse(response)
File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/idlelib/rpc.py", line 267, in decoderesponse
raise what
UnicodeEncodeError: 'UCS-2' codec can't encode characters in position 8-8: Non-BMP character not supported in Tk我完全被卡住了!我已经尝试了所有发布的解决方案,但都没有奏效。如果可以,请帮助我!
另外,我已经修改了令牌,别再试了。
发布于 2018-07-04 04:54:39
您的问题是,您试图在空闲编辑器中运行代码。IDLE编辑器使用UCS-2编码,因此当您尝试打印带有奇怪的unicode字符和表情符号的用户名字符串时,IDLE窗口无法显示它。
我建议使用字符串的ascii()进行调试,这将打印unicode的python表示,而不是实际的代码点(不能打印取决于目标窗口):
print(ascii("I am the" + client.user.name))https://stackoverflow.com/questions/51162636
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