解析HTML以从表行中提取数据

Question

我正在使用BeautifulSoup从纳斯达克网站提取股票信息。我想特别从HTML页面上的表行中检索信息，但总是得到一个错误(第12行)。

    #import html-parser
    from bs4 import BeautifulSoup
    from requests import get

    url = 'https://www.nasdaq.com/symbol/amzn' #AMZN is just an example
    response = get(url)

    #Create parse tree (BeautifulSoup Object)
    soup = BeautifulSoup(response.text, 'html.parser')
    data = soup.find_all(class_= 'column span-1-of-2')

    table = data.find(class_= 'table-row') #This is where the error occurs
    print(table)

Answer 1

您可以这样做，以便从表行中获取数据。

import requests
from bs4 import BeautifulSoup
import re

r = requests.get("https://www.nasdaq.com/")

print(r)
soup = BeautifulSoup(r.content, 'html.parser')
data = soup.find('table',{'id':'indexTable', 'class':'floatL marginB5px'}).script.text
matches = re.findall(r'nasdaqHomeIndexChart.storeIndexInfo(.*);\r\n', data)
table_rows = [re.findall(r'\".*\"', row) for row in matches]
print(table_rows)

table_rows是包含表数据的列表的列表。