我正在做一个自动程序(C#,不是C++),我需要在表单中获得一个RichTextBox。我使用Spy++来获取标题和类名,但是FindWindowEx总是找不到RichTextBox,而GetLastError获取的是单词0。这是一个简单的例子。
IntPtr parent = FindWindow(null, "Form1");
if (parent!=IntPtr.Zero) {
//find test1 textbox
IntPtr child = FindWindowEx(parent, 0,null, "test1");
if (child!=IntPtr.Zero) {
SendMessage(child, 0x000c, 0, lParam: "test");
} else {
Console.WriteLine("textbox can't be found");
}
//find test2 richtextbox
IntPtr childRich = FindWindowEx(parent, 0, null, "test2");
if (childRich != IntPtr.Zero) {
SendMessage(child, 0x000c, 0, lParam: "test");
} else {
Console.WriteLine("richtextbox can't be found");
}
} else {
Console.WriteLine("Form1 can't be found");
}

但是结果是richtextbox can't find。帮帮我。
发布于 2018-06-01 16:42:57
我真的不认为这是最好的方法,但它是有意义的。
对于这种特定情况,您可以搜索表单中的所有处理程序,然后更改所需的处理程序。
var iHandle = Win32.FindWindow(null, "Form1");
var allItems = Win32.GetAllChildrenWindowHandles((IntPtr)iHandle, int.MaxValue);
Win32.SendMessage(allItems[1], 0x000c, 0, lParam: "Now you can change the text!");我已经测试过了,allItems1将始终是相同的项目,我认为这是项目在winForm中从上到下排序的方式。
我为Win方法使用了第二个类:
public class Win32
{
public const int WM_SETTEXT = 0X000C;
public static List<IntPtr> GetAllChildrenWindowHandles(IntPtr hParent, int maxCount)
{
var result = new List<IntPtr>();
int ct = 0;
IntPtr prevChild = IntPtr.Zero;
IntPtr currChild = IntPtr.Zero;
while (true && ct < maxCount)
{
currChild = FindWindowEx(hParent, prevChild, null, null);
if (currChild == IntPtr.Zero) break;
result.Add(currChild);
prevChild = currChild;
++ct;
}
return result;
}
[DllImport("user32.dll")]
public static extern IntPtr FindWindowEx(IntPtr hwndParent, IntPtr hwndChildAfter, string lpszClass, string lpszWindow);
[DllImport("User32.dll")]
public static extern int FindWindow(string strClassName, string strWindowName);
}编辑:获取所有子窗口句柄的方法,取自:https://jamesmccaffrey.wordpress.com/2013/02/03/getting-all-child-window-handles-using-c-pinvoke-findwindowex/
https://stackoverflow.com/questions/50638850
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