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问MySQL联合表按列分组
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Stack Overflow用户
提问于 2018-05-20 20:13:34
回答 2查看 244关注 0票数 0

我有两张桌子searches和recommended_searches。两者都有两列id和keyword

搜索表

代码语言:javascript
复制
id | keyword 
1  | one 
2  | two 
3  | one 
4  | one 
5  | two
6  | one

recommended_searches表

代码语言:javascript
复制
id | key 
1  | two 
2  | two 
3  | one 
4  | two 
5  | two
6  | one

我使用此查询返回搜索表中每个关键字的计数

代码语言:javascript
复制
SELECT keyword, count(*) as cnt FROM searches GROUP BY keyword ORDER by cnt DESC

下面的查询是推荐的

代码语言:javascript
复制
SELECT keyword, count(*) as cnt FROM recommended_searches GROUP BY keyword ORDER by cnt DESC

我想在这两个表上按键分组,但是搜索表使用cnt,recommended_search使用recommended_cnt。这是为了让我可以根据表格类型进行排序,例如按推荐的搜索排序。

代码语言:javascript
复制
SELECT keyword, count(*) as cnt FROM searches
UNION ALL
SELECT keyword, count(*) as recommended_cnt FROM recommended_searches
GROUP BY keyword ORDER by recommended_cnt DESC

如何同时返回cnt和recommended_cnt?我尝试了上面的方法,但是没有起作用。

我想要像这样的结果

代码语言:javascript
复制
Array(
[keyword] => one
[cnt] => 4
[recommended_cnt] => 2
);

Array(
[keyword] => two
[cnt] => 2
[recommended_cnt] => 4
);
EN

回答 2

Stack Overflow用户

发布于 2018-05-20 20:21:48

将计数放在两个子查询的不同列中。

代码语言:javascript
复制
SELECT `key`, MAX(cnt) AS cnt, MAX(recommended_cnt) AS recommended_cnt
FROM (
    SELECT `keyword` AS `key`, COUNT(*) AS cnt, 0 AS recommended_cnt
    FROM searches
    GROUP BY `key`
    UNION ALL
    SELECT `key`, 0 AS cnt, COUNT(*) AS recommended_cnt
    FROM recommended_searches
    GROUP BY `key`
) AS x
GROUP BY `key`

DEMO

票数 2
EN

Stack Overflow用户

发布于 2018-05-20 20:23:30

你想要的不是一个联合,你想要的是它们之间的连接。

代码语言:javascript
复制
SELECT a.keyword, a.cnt AS cnt, b.cnt AS cnt_recommended
FROM
  (SELECT keyword, count(*) as cnt FROM searches GROUP BY keyword ORDER by cnt DESC) as a
LEFT OUTER JOIN
  (SELECT keyword, count(*) as cnt FROM recommended_searches GROUP BY keyword ORDER by cnt DESC) as b
  ON a.keyword = b.keyword
GROUP BY a.keyword
ORDER BY ...

这将连接两个查询,并分别给出它们的计数。根据您的需求,连接类型可能会有所不同。

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/50434731

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