2题猜数游戏

Question

因此，正如标题所说，我有两个问题(据我所知)，第一个问题是当我键入一个数字退出它时，我如何使用is digit验证它并打印一条错误消息；第二个问题是如果我猜出一个数字，假设是20，它会说太低，如果我放入21，它会说太高，这里是命令提示符

输入1到100之间的数字或输入exit退出: 20太低，请重试输入1到100之间的数字或输入exit退出: 21太高，请重试

import random
guess = '0'
while (guess) != exit:
    answer = random.randrange(1,100)
    answer = str(answer)
    guess = input('Enter a number between 1 and 100 or enter exit to exit: ')
    guess = (guess)
    if guess == answer:
        print('Correct')
    elif guess > answer :
        print('Too high, try again')
    elif guess < answer :
        print('Too low, try again')

Answer 1

你可以向isdigit查询

#!/usr/bin/env python

import random
guess = '0'
while (guess) != exit:
    answer = random.randrange(1,100)
    answer = str(answer)
    guess = input('Enter a number between 1 and 100 or enter exit to exit: ')
    if not guess.isdigit(): 
        if guess == "exit":
            break
    guess = (guess)
    if guess == answer:
        print('Correct')
    elif guess > answer :
        print('Too high, try again')
    elif guess < answer :
        print('Too low, try again')