用Python - Comma Code自动化那些无聊的东西

Question

所以我想出了一个可行的解决方案，不使用牛津逗号，有没有一种更简洁的方法？

def stringy(spam):
    output = ""
    for thing in spam[:-1]: 
        output = output + thing + ", "
    output = output[:-2] + " and " + spam[-1] #removes the last 2 chars 
    return output

spam = ['cats','cats','cats','cats', 'apples', 'bananas', 'tofu', 'cats']

print(stringy(spam))`

Answer 1

def list1(name):
    name = name.insert(len(name)-1, 'and')
    for i in range(len(spam)-2):

        print(spam[i] ,end=', ' )
    print(spam[-2], end=' ')    
    print(spam[-1],end='')



spam = ['apples', 'bananas', 'tofu', 'cats' , 'hello']
list1(spam)

Answer 2

尝试以下操作：-

def stringy(spam):
    if len(spam) < 2:
        return ' and '.join(spam)
    else:
        return ', '.join(spam[:-1]) + ' and '+spam[-1]

spams = [['cats','cats','cats','cats', 'apples', 'bananas', 'tofu', 'cats'],['tofu', 'cats'],[]]

for spam in spams:
    print(stringy(spam))

Answer 3

这基本上就是@Azat Ibrakov在一行代码中所做的，我只想警告一下python中字符串操作的+。

def commanize(spam: list):
    if len(spam) >= 2:
        comma_str = ', '.join(spam[:-1])
        return ' and '.join([comma_str, spam[-1]])
    else:
        return spam[0]

assert commanize(['a', 'b', 'c'])  == 'a, b and c'
assert commanize(['a', 'b'])  == 'a and b'
assert commanize(['a'])  == 'a'