如何读取包含多个拆分的Java文件

Question

BB [FL:60 BT:10 SG:20 MK:10 | 12] 

我在一个文本文件中有上述数据，我需要单独获取整数值

简而言之，第一个BB用":“代表食物类型，用"|”代表制作时间

如何使用文件阅读器在java中获取这5个参数谢谢

Answer 1

在这里使用正则表达式匹配器，并迭代您的输入字符串，匹配您的纯数字：

String input = "BB [FL:60 BT:10 SG:20 MK:10 | 12]";
String regex = "\\d+(?=[^0-9.])";
List<Integer> vals = new ArrayList<>();

Pattern p = Pattern.compile(regex);
Matcher m = p.matcher(input);

while (m.find()) {
    vals.add(Integer.parseInt(m.group(0)));
}

for (int val : vals) {
    System.out.println("Found an integer: " + val);
}

Found an integer: 60
Found an integer: 10
Found an integer: 20
Found an integer: 10
Found an integer: 12

​

Demo

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Answer 2

拆分、拆分、修剪和拆分：

-> String code = "BB [FL:60 BT:10 SG:20 MK:10 | 12]"
|  Added variable code of type String with initial value "BB [FL:60 BT:10 SG:20 MK:10 | 12]"

-> String[] mattime = code.split ("[\\]\\[\\|]");
|  Modified variable mattime of type String[] with initial value [Ljava.lang.String;@2286778
|    Update overwrote variable mattime

-> mattime [1]
|  Expression value is: "FL:60 BT:10 SG:20 MK:10 "
|    assigned to temporary variable $32 of type String

-> String[] elem = mattime [1].split (" ")
|  Modified variable elem of type String[] with initial value [Ljava.lang.String;@13a5fe33
|    Update overwrote variable elem

-> for (String e: elem) println (e);
FL:60
BT:10
SG:20
MK:10

-> for (String e: elem) {println (e); String [] kv = e.trim().split (":") ; println (kv[0] + " : " + Integer.parseInt (kv[1])); }
FL:60
FL : 60
BT:10
BT : 10
SG:20
SG : 20
MK:10
MK : 10