从字符串中获取三元组字符

Question

定义get_triples_dict()函数，该函数将一个文本字符串作为参数传递。该函数首先将参数字符串转换为小写，然后返回一个字典，字典中的键都是文本中唯一的连续三个字母字符，相应的值是这三个连续字母字符在文本中出现的次数。使用isalpha()方法检查字符是否为字母。字典应该只包含出现多次的条目。在创建并填充字典之后，您需要删除具有相应值1的所有键-值对。

我需要帮助来编写这个get_triples_dict函数：

def get_triples_dict(text):


def test_get_triples_dict():
    print("1.")
    print_dict_in_key_order(get_triples_dict('super, duper'))
    print("\n2.")
    print_dict_in_key_order(get_triples_dict("ABC ABC ABC"))
    print("\n3.")
    print_dict_in_key_order(get_triples_dict("Sometimes the smallest things make more room in your heart"))
    print("\n4.")
    print_dict_in_key_order(get_triples_dict("My favourite painting is the painting i did of my dog in that painting in my den"))

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Answer 1

我不会为你完成你的作业，但下面是你需要做的一个很好的开始。我相信您可以编写代码对单词进行排序并打印出字典。一定要仔细研究每一行，一旦你有了大致的想法，就写出你自己的版本。

def get_triples_dict(text):
    d = dict()
    text = text.lower().replace(' ', '') # set to lowercase and remove spaces
    for i in range(len(text) - 2): # stops early to prevent index out of bounds exception
        bit = text[i: i + 3] # characters in groups of 3
        if all(c.isalpha() for c in bit): # all characters must be alphabetic
            if not bit in d: # if there's no entry
                d[bit] = 0
            d[bit] += 1
    copy = d.copy() # we cannot remove items from a list we are looping over (concurrent modification exception)
    for key, value in copy.items():
        if value == 1: # remove items with counts of 1
            d.pop(key)
    return d