如何使用value元素作为第二个元素的key？

Question

我有如下的json：

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[{"id":19,"text":"A-Z CLI 19/03/2015"},{"id":36,"text":"Wavetel Retail1"},{"id":37,"text":"Wavetel A2Z Platinum"},{"id":38,"text":"Wavetel A2Z Gold"},{"id":40,"text":"mysql test2"},{"id":63,"text":"inbound test"},{"id":137,"text":"testpbxretail"},{"id":144,"text":"INBOUND CLI"},{"id":145,"text":"0800142324"},{"id":164,"text":"Rategenerator-Otto-Test"},{"id":165,"text":"Rategenerator-Otto-Test 2 "},{"id":166,"text":"Rategenerator-Otto-Test 3 "},{"id":171,"text":"VasimRateGenerator"}]

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我想用最短的方式来使用第一个元素的值(19)作为第二个元素的关键字(而不是'text')有多个元素，所以可以通过循环来完成。然后移除之后的第一个元素。

所以我希望输出如下(例如，对于第一个元素{"id":19，"text":"A-Z CLI 19/03/2015"})：

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[{"19":"A-Z CLI 19/03/2015"}]

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Answer 1

您可以通过将callback函数作为参数传递来使用map方法。

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let arr = [{"id":19,"text":"A-Z CLI 19/03/2015"},{"id":36,"text":"Wavetel Retail1"},{"id":37,"text":"Wavetel A2Z Platinum"},{"id":38,"text":"Wavetel A2Z Gold"},{"id":40,"text":"mysql test2"},{"id":63,"text":"inbound test"},{"id":137,"text":"testpbxretail"},{"id":144,"text":"INBOUND CLI"},{"id":145,"text":"0800142324"},{"id":164,"text":"Rategenerator-Otto-Test"},{"id":165,"text":"Rategenerator-Otto-Test 2 "},{"id":166,"text":"Rategenerator-Otto-Test 3 "},{"id":171,"text":"VasimRateGenerator"}]

arr = arr.map(function({id, text}){
    return { [id]: text };
});
console.log(arr);

​

或者只使用一个arrow函数。

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let arr = [{"id":19,"text":"A-Z CLI 19/03/2015"},{"id":36,"text":"Wavetel Retail1"},{"id":37,"text":"Wavetel A2Z Platinum"},{"id":38,"text":"Wavetel A2Z Gold"},{"id":40,"text":"mysql test2"},{"id":63,"text":"inbound test"},{"id":137,"text":"testpbxretail"},{"id":144,"text":"INBOUND CLI"},{"id":145,"text":"0800142324"},{"id":164,"text":"Rategenerator-Otto-Test"},{"id":165,"text":"Rategenerator-Otto-Test 2 "},{"id":166,"text":"Rategenerator-Otto-Test 3 "},{"id":171,"text":"VasimRateGenerator"}]

arr = arr.map(({id, text}) =>  ({[id]: text}));
console.log(arr);

​