熊猫图22系列，11幅图，1幅图

Question

我可以在11个图表和1个图表中绘制11个系列：

NG = [1,2,3,4,5,6,7,8,9,10,11]
serieslist = []

for n in NG:
    l = [1,2,3,4,5,6]
    df = pd.DataFrame(l)
    serieslist.append(df)

df = pd.concat(serieslist, axis = 1)
df.plot(grid = 1, subplots = True, layout = (6,2), sharey = True)

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如何在1个图中绘制22个系列(其中2个应始终在一个图中)？这意味着11张图中有22张图。下面的代码只给出了22个图表：

NG = [1,2,3,4,5,6,7,8,9,10,11]
serieslist = []

for n in NG:
    l = [1,2,3,4,5,6]
    df = pd.DataFrame(l)
    serieslist.append(df)
    serieslist.append(df)


df = pd.concat(serieslist, axis = 1)
df.plot(grid = 1, subplots = True, layout = (12,2), sharey = True)

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编辑:这不是我想要的100%的解决方案，但它看起来更漂亮：

import pandas as pd

NG = [1,2,3,4,5,6,7,8,9,10,11]
dflist1 = []
dflist2 = []

l = [1,2,3,4,5,6]
b = [6,5,4,3,2,1]


for n in NG:
    df = pd.DataFrame(l)
    dflist1.append(df)
    df = pd.concat(dflist1, axis = 1)
    df2 = pd.DataFrame(b)
    dflist2.append(df2)
    df2 = pd.concat(dflist2, axis = 1)

df.plot(grid = 1, subplots = True, layout = (12,1), sharey = True)
df2.plot(grid = 1, subplots = True, layout = (12,1), sharey = True)

输出:2图。现在如何将这些图组合成一个图形呢？

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Answer 1

您可以对此matplotlib.pyplot.subplot使用。

 import matplotlib.pyplot as plt 

在单个单元格中：

遍历由输入i in range(11)

• In

• i +

组成的值

• I
  • DataFrame plt.subplot(6, 2, i + 1)
  • Plot
    • DataFrame

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