键入transfer int to str

Question

问题：

Given a string containing uppercase alphabets and integer digits (from 0 to 9), write a function to return the alphabets in the order followed by the sum of digits.

我的代码：

import re

class Solution:
    def rearrange(self, str):
        # Write your code here
        if str == "":
            return str
        sum = 0
        letter = []
        for i in range(len(str)):
            if re.search("([A-Z])", str[i]):
                letter.append(str[i])
            else:
                sum += int(str[i])
        letsort = sorted(letter)
        letstr = "".join(letsort)
        result = letstr + str(sum)
        return result

错误：

Traceback (most recent call last):
  File "/code/Main.py", line 20, in
    ans = solution.rearrange(str)
  File "/code/Solution.py", line 20, in rearrange
    result = letstr + str(sum)
  TypeError: 'str' object is not callable

我不明白其中的原因。

Answer 1

str是Python语言中的保留字，您可以通过将rearrange()的第二个参数命名为str来覆盖它。更改rearrange()第二个参数的名称即可完成此操作。

Answer 2

您已将变量命名为str -与用于转换为字符串的内置函数同名。你需要重命名它，试试这个：

import re
class Solution:
    def rearrange(self, str_in):
        # Write your code here
        if str_in == "":
            return str_in
        sum = 0  
        letter = []
        for i in range(len(str_in)):    
            if re.search("([A-Z])", str_in[i]):
                letter.append(str_in[i])
            else:
                sum += int(str_in[i])
        letsort = sorted(letter)
        letstr = "".join(letsort)
        result = letstr + str(sum)
        return result