我尝试使用#lang plai-typed用DrRacket编写简单的模式匹配器,如下所示:
#lang plai-typed
(define-type Activity
[kind (type : string) (description : string)]
)
(define-type Hacktivity
[activity1 (activity : Activity)]
[activity2 (activity : Activity)]
[activity3 (activity : Activity)]
)
(define (good? [h : Hacktivity]) : boolean
(type-case Hacktivity h
[activity1 (activity) (string=? activity-kind-type "Analyze")]
[activity2 (activity) (string=? "Analyze" "Analyze")]
[activity3 (activity) (string=? "Analyze" "Analyze")]
)
)然而,不能正确地理解“活动-种类-类型”部分。任何帮助都是非常感谢的。提前谢谢。
发布于 2018-04-05 15:55:46
我可以用下面的方法解决这个问题:
#lang plai-typed
(define-type Activity
[kind (type : string) (description : string)]
)
(define-type Hacktivity
[activity1 (activity : Activity)]
[activity2 (activity : Activity)]
[activity3 (activity : Activity)]
)
(define analyze : Activity (kind "Analyze" "Test description"))
(define hack : Hacktivity (activity1 analyze))
(define (good? [h : Hacktivity]) : boolean
(type-case Hacktivity h
[activity1 (activity)
(type-case Activity activity
[kind (type description) (string=? type "Analyze")])]
[activity2 (activity)
(type-case Activity activity
[kind (type description) (string=? type "Analyze")])]
[activity3 (activity)
(type-case Activity activity
[kind (type description) (string=? type "Analyze")])])
)如果您有嵌套类型定义,则需要以嵌套方式应用type-case。
https://stackoverflow.com/questions/49666423
复制相似问题