Python水平拆分list

Question

我有这样的代码：

url = requests.get('https://sneakernews.com/release-dates/').text
soup = BeautifulSoup(url, 'html.parser')

tags = soup.find_all('div', {'class': 'col lg-2 sm-3 popular-releases-box'})

for tag in tags:
    link = tag.find('a').get('href')
    tag1 = str(tag.text)
    tag2 = tag1.splitlines()
    print(tag2)
    if link == 'javascript:void(0);':
        link = 'Link not available'

我有这样的输出：

['March  ', 'OFF WHITE x Nike Air VaporMax']
['04.12  ', 'Nike Air VaporMax 97 "Silver Bullet"']
['April  ', 'adidas Yeezy Desert Rat 500 "Blush"']
['05.15  ', 'ACRONYM x Nike Air VaporMax MOC 2']

上面的输出是垂直的2个列表，我试着让每一行都成为一个列表。

Answer 1

使用几个list comprehensions和zip()，可以做到如下所示：

代码：

the_tags = [[x.strip() for x in tag.text.splitlines()] for tag in tags]
result = [x for x in zip(*the_tags)]

测试代码：

import requests
from bs4 import BeautifulSoup

url = requests.get('https://sneakernews.com/release-dates/').text
soup = BeautifulSoup(url, 'html.parser')

tags = soup.find_all('div', {'class': 'col lg-2 sm-3 popular-releases-box'})

the_tags = [[x.strip() for x in tag.text.splitlines()] for tag in tags]
print([x for x in zip(*the_tags)])

结果：

[('March', '04.12', 'April', '05.15'), 
 ('OFF WHITE x Nike Air VaporMax', 'Nike Air VaporMax 97 "Silver Bullet"', 
  'adidas Yeezy Desert Rat 500 "Blush"', 'ACRONYM x Nike Air VaporMax MOC 2'
 )
]