是否将Observable<boolean[]>拆分为Observable<boolean>[]？

Question

在我的一个组件中，我有以下几个：

// this.can... are booleans
redux
  .watch(state => state.userInfo.access.current)
  .takeUntil(this.done)
  .subscribe(access =>
    [this.canPartners, this.canServices, this.canTens, this.canWorklist] =
    [EPermission.Partner, EPermission.Worklist, EPermission.Tens, EPermission.Worklist]
      .map(ii => access[ii] >= EAccess.Read));

我想知道怎样才能将可观察对象分解成这样的东西：

// this.can...$ are Observable<boolean>s
[this.canPartners$, this.canServices$, this.canTens$, this.canWorklist$] = redux
  .watch(ReduxGetters.userAccess)
  .takeUntil(this.done)
  .?mapSplit?(access => [EPermission.Partner, EPermission.Worklist, EPermission.Tens, EPermission.Worklist].map(ii => access[ii] >= EAccess.Read));

更新

我使用的是rxjs BTW，这意味着我受到那里提供的运算符的限制。我得到的最接近的结果如下：

const result$: Observable<Observable<boolean>[]> = redux
  .watch(ReduxGetters.userAccess)
  .takeUntil(this.done)
  .map(access =>
    [EPermission.Partner, EPermission.Worklist, EPermission.Tens, EPermission.Worklist]
      .map(ii => Observable.of(access[ii] >= EAccess.Read)));

...now我“只是”需要去掉可观察到的包装器...

Answer 1

您可能想要尝试这样的操作

// this.can...$ are Observable<boolean>s
redux
  .watch(ReduxGetters.userAccess)
  .takeUntil(this.done)
  .reduce((accumulatorArray, current) => {
    accumulatorArray.push(current  >= EAccess.Read)
  }, new Array<boolean>())
  .submit(
    arrayOfBooleans => [this.canPartners$, this.canServices$, this.canTens$, this.canWorklist$] = arrayOfBooleans
  )

我不能尝试这个，但也许能行得通